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jolli1 [7]
2 years ago
12

Simplify 2 (8r2+r)-4r

Mathematics
2 answers:
Rainbow [258]2 years ago
5 0
2(8r2+r)-4r

2(17r)-4r

34r-4r

30r
taurus [48]2 years ago
4 0
16r^2+ 2r -4r 16r^2 - 2r 2r ( 8r -1)
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HELP WILL NAME BRAINLIEST
Anvisha [2.4K]

Answer

it was on my test

6 0
3 years ago
What is 2/100000 as a decimal
blsea [12.9K]
2.0e-6
Is the answer to your question

6 0
3 years ago
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My Notes A large manufacturing plant uses lightbulbs with lifetimes that are normally distributed with a mean of 1600 hours and
Evgen [1.6K]

Answer:

The bulbs should be replaced each 1436.9 hours.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 1600, \sigma = 70

How often should the bulbs be replaced so that no more than 1% burn out between replacement periods?

This is the first percentile of hours. So it is X when Z has a pvalue of 0.01.

So it is X when Z = -2.33.

Z = \frac{X - \mu}{\sigma}

-2.33 = \frac{X - 1600}{70}

X - 1600 = -2.33*70

X = 1436.9

The bulbs should be replaced each 1436.9 hours.

6 0
3 years ago
Seis manzanas y 8 peras cuestan $26. ¿Cuanto cuesta cada pera y cada manzana sabiendo que cada manzana cuesta el triple de lo qu
Rom4ik [11]

Usando un sistema de ecuaciones, se encuentra que

  • Cada manzana cuesta $3.
  • Cada pera cuesta $1.

-----------------------

  • Un sistema de ecuaciones soluciona esta pergunta.
  • El custo de una manzana es x.
  • El custo de una pera es y.

-----------------------

  • <u>Seis manzanas y 8 peras cuestan $26</u>, o sea, 6x + 8y = 26
  • <u>Cada manzana cuesta el triple de cada pera</u>, o sea, x = 3y

-----------------------

Primero, encontramos el cuesto de una pera, substituyendo la segunda en la primera ecuación.

6x + 8y = 26

6(3y) + 8y = 26

18y + 8y = 26

26y = 26

y = \frac{26}{26}

y = 1

Cada pera cuesta $1.

-----------------------

<u>Cada manzana cuesta el triple de cada pera</u>, o sea, x = 3y = 3(1) = 3.

Cada manzana cuesta $3.

Se encuentra um problema similar en brainly.com/question/24646137

6 0
2 years ago
A support wire extends from the top of a 225 feet radio tower to the ground and makes an angle of 64° with the ground. How long
aniked [119]

Answer:

250.34 feet

Step-by-step explanation:

Find attached to this answer and appropriate diagram.

From this question, we can see that this is a trigonometric function

The height of the radio tower = 225 feet = Opposite side

θ = Angle 64°

In the question we are told to find the length of the wire needed to reach from the top of the tower to the ground.

From the attached diagram, we can see that that is equivalent to finding the hypotenuse.

Hence, we are using the Trigonometric function of Sine.

sin θ = Opposite side/ Hypotenuse side

sin 64 = 225 feet/ Hypotenuse

Cross multiply

sin 64 × Hypotenuse = 225 feet

Divide both sides by sin 64

Hypotenuse = 225 feet / sin 64

Hypotenuse = 250.33543661 feet

Approximately = 250.34 feet

Therefore, the length of the wire needed to reach from the top of the tower to the ground is 513.3 feet.

7 0
3 years ago
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