The polynomial a(x) = -18x² - 6x + 12 is the dividend of the polynomial division
The quotient q(x) is 0 and the remainder r(x) is -18x² - 6x + 12
<h3>How to divide the polynomial?</h3>
The polynomial functions are given as:
a(x) = -18x² - 6x + 12
b(x) = 3x³ + 9x - 1
The quotient equation is given as:
a(x)/b(x) = q(x) + r(x)/b(x)
Since the degree of the dividend a(x) is less than the degree of the divisor b(x), then it means that the value of the quotient q(x) is:
q(x) = 0
And the remainder r(x) is:
r(x) = a(x)
Substitute known values
r(x) = -18x² - 6x + 12
Hence, the quotient q(x) is 0 and the remainder r(x) is -18x² - 6x + 12
Read more about polynomial division at:
brainly.com/question/25289437
Answer:
the 4th one
Step-by-step explanation:
Around 0.02 or more precise, 0.02083
X^2 - 8x-9=0
D = b^2- 4*a*c = 64- 4* (-9) = 64+36=100 =10^2
X1 = (8-10)/2 = -1
X2= (8+10)/2= 9
Answer:
the third one 10 cm, 9cm 9cm
