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sladkih [1.3K]
2 years ago
11

A state offers specialty license plates that contain 3 letters followed by 2 numbers. License plates are assigned randomly. All

license plates are equally likely. Find the number of possible license plates that can be issued using this system.
A. 98 possible license plates
B. 36 possible license plates
C. 1,757,600 possible license plates
D. 17,576,000 possible license plates
Mathematics
1 answer:
Maslowich2 years ago
4 0

Answer:

Step-by-step explanation:

# of ways to succeed: 10*10*10*3*25*25--# of possible plates: 10*10*10*26*26*26----P(exactly one W) = [10^3*3*25^2]/[10^3*26^3] = 3*25^2/26^2 = 1875/17576

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A shelf in your room can hold at most 3030 pounds. There are 1212 pounds of books already on it. Which inequality represents the
EastWind [94]
<span>number of pounds you can add to the shelf</span> ≤ 1818 pounds
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3 years ago
X+49=75 <br>solve this equation by undoing
sergij07 [2.7K]
Hi there!

First, we "undo" the +49 by subtracting it from both sides of the equation:

x + 49 = 75
x = 75 - 49
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Hope this helps!

8 0
3 years ago
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How much of a 14% solution of iodine should be added to 89 ounces of a 47% iodine solution to get a 29% solution
Andrews [41]
We have 89 ounces of 47% iodine.
We will add "x" ounces of 14% iodine to get a 29% iodine solution.
89 * .47 + .14x = .29 * (89 + x)
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Source:
http://www.1728.org/mixture.htm


3 0
3 years ago
n △ABC, point P∈ AB is so that AP:BP=1:3 and point M is the midpoint of segment CP. Find the area of △ABC if the area of △BMP is
monitta

Answer: The area of ABC is 56 m².

Explanation:

It is given that in △ABC, point P∈ AB is so that AP:BP=1:3 and point M is the midpoint of segment CP.

Since point P divides the line AB in 1:3, therefore the area of triangle APC and BPC is also in ratio 1:3. To prove this draw a perpendicular h on AB from C.

\frac{\text{Area of } \triangle BCP}{\text{Area of } \triangle ABC} =\frac{\frac{1}{2}\times BP\times CH}{\frac{1}{2}\times AB\times CH} =\frac{BP}{AB}= \frac{3}{4}

Since the area of BPC is \frac{3}{4}th part of total area, therefore area of APC is  \frac{1}{4}th part of total area.

The point M is the midpoint of CP, therefore the area of BMP and BMC is equal by midpoint theorem.

\text{Area of } \triangle BMP=\text{Area of } \triangle BMC

21=\text{Area of } \triangle BMC

Area of BPC is,

\text{Area of } \triangle BPC=\text{Area of } \triangle BMP+\text{Area of } \triangle BMC

\text{Area of } \triangle BPC=21+21

\text{Area of } \triangle BPC=42

Area of APC is,

\text{Area of } \triangle APC=\frac{1}{3}\times \text{Area of } \triangle BPC

\text{Area of } \triangle APC=\frac{1}{3}\times 42

\text{Area of } \triangle APC=14

Area of ABC is,

\text{Area of } \triangle ABC=\text{Area of } \triangle APC+\text{Area of } \triangle BPC

\text{Area of } \triangle ABC=14+42=56

Therefore, the area of ABC is 56 m².

5 0
3 years ago
What me the answer to s-8=9
Irina-Kira [14]

Answer: -2 i believe because if you take and subtract one from 8 you should get 9

Step-by-step explanation:

5 0
2 years ago
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