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alexira [117]
3 years ago
9

Express 16 as difference of two prime numbers

Mathematics
1 answer:
True [87]3 years ago
5 0
16 = 19-3

19 and 3 are both prime numbers, and the difference is 16.
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Step-by-step explanation:

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3 years ago
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Find the domain in the given ordered pairs.<br> {(2,8). (1,7), (2,9). (4, 6)}
Vlada [557]

Answer:

Domain: {1,2,4}

Step-by-step explanation:

The domain is the input values

We normally list the value in order from smallest to largest and only list the values one time if they appear more than once

Domain: {1,2,4}

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Confused on this one. I need someone to help me out.
Arlecino [84]
The answer is T=PV/nR

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3 years ago
If you take out a loan for $550 at 7.2% simple interest and make no payments for 6 months how much do you owe in total
Sergeu [11.5K]

Answer:

$569.80

Step-by-step explanation:

We can use the simple interest formula for this:

A = P (1 + rt)

<em>P = initial balance </em>

<em>r = annual interest rate </em>

<em>t = time </em>

<em />

First, change 7.2% into its decimal form:

7.2% -> \frac{7.2}{100} -> 0.072

Next, since we are calculating for 6 months (1/2 of a year), the annual interest rate will be 0.5. Now, plug in the values:

A=550(1+(0.072)(0.5))

A=569.80

The total amount owed in 6 months is $569.80

8 0
3 years ago
If (ax^2 + 3x + 2b) - (5x^2+bx-3c)=3x^2-9, what is the value of A + B + C?
Rina8888 [55]

Answer:

We have the equation:

(ax^2 + 3x + 2b) - (5x^2+bx-3c)=  3x^2 - 9

First, move all to the left side.

(ax^2 + 3x + 2b) - (5x^2+bx-3c) - 3x^2 + 9 = 0

Now let's group togheter terms with the same power of x.

(a - 5 - 3)*x^2 + (3 - b)*x + (2b + 3c + 9) = 0.

This must be zero for all the values of x, then the things inside each parenthesis must be zero.

1)

a - 5 - 3 = 0

a = 3 + 5 = 8.

2)

3 - b = 0

b = 3.

3)

2b + 3c + 9 = 0

2*3 + 3c + 9 = 0

3c = -6 - 9 = -15

c = -15/3 = -5

Then we have:

a = 8, b = 3, c = -5

a + b + c = 8 + 3 - 5 = 6

8 0
3 years ago
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