Question

The display provided from technology available below results from using data for a smartphone carrier's data speeds at airports to test the claim that they are from a population having a mean less than 6.00 Mbps. Conduct the hypothesis test using these results. Use a 0.05 significance level. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses?
T-Test


μ<4.00


t=-3.033077


p=0.002025


x=3.48


Sx=1.150075


n=45

Answer 1

Answer:

Kindly check explanation

Step-by-step explanation:

Given the T test output :

T-Test

μ<4.00

t=-3.033077

p=0.002025

x=3.48

Sx=1.150075

n=45

Given that population mean, μ = 6

Confidence level, α = 0.05

The hypothesis :

H0 : μ = 6.00

H1 : μ < 6.00

From the t test output given :

The test statistic :

T = -3.033077

T = - 3.03 (2 decimal places)

The Pvalue :

P = 0.002025

Pvalue = 0.002 (3 decimal places)

The conclusion :

Decision region ; Reject H0 : if Pvalue < α

Since ; Pvalue < α

Reject H0 ; There is sufficient evidence to support claim that sample is from a population with a mean less than 6.