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fgiga [73]
2 years ago
9

What is the diameter of a circle if the radius is 400 millimeters​

Mathematics
2 answers:
Luda [366]2 years ago
5 0

Answer:

800

Step-by-step explanation:

d=2r=2·400=800

Fiesta28 [93]2 years ago
4 0

Answer:

The diameter of the circle is 800 millimeters

Step-by-step explanation:

The diameter of a circle is twice as much as a radius.

400 x 2 = 800 millimeters

I Hope That This Helps! :)

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I can Multiply a 11x6 matric by a 6x7 matrix. The resulting matrix will be ??? Can somebody help me
Bumek [7]

Answer:

The resulting matrix will be 11 * 7

Step-by-step explanation:

Given

Matrices 11 * 6 multiplied by 6 * 7

Required

The dimension of the resulting matrix

When a matrix a * b is multiplies by a matrix b * c, the resulting matrix will be: a * c

In this case:

a * b = > 11 * 6

b * c => 6 * 7

So, the resulting matrix will be:

a * c => 11 * 7

3 0
2 years ago
Did the scale factor of 0.75 enlarge reduce or stay the same?
elixir [45]

Answer:

\huge\boxed{\sf Reduces}

Step-by-step explanation:

Since the scale factor of 0.75 is less than 1, So the dilated image is a reduced image.

Thus the scale factor of 0.75 reduces the dilated image.

\rule[225]{225}{2}

Hope this helped!

<h3>~AnonymousHelper1807</h3>
6 0
2 years ago
Read 2 more answers
Please Help
Anna35 [415]

Answer:

1.5 Oz because it's just a random guess hopefully I'm right

I think

7 0
2 years ago
Question: Ned took a test with 25 questions. He lost 4 points for each of the 6 questions he got wrong and earned an additional
Dima020 [189]
Your thoughts are correct; Ned loses 14 points overall.

The reason the correctly answered questions do not factor into the answer is because that is not what the question is asking. Correct answers are not even mentioned :)
6 0
2 years ago
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Factor using the identity: a3 + b3 = (a + b)(a2 – ab + b2) 8z3 + 27
vivado [14]

Answer:  this is our required factor i.e.

8z^3+27=(2z+3)(4z^2-6z+9)

Explanation:

Since we have given that

8z^3+27

As we know the identity , which says that

a^3+b^3=(a+b)(a^2-ab+b^2)

So, we can use this here ,

8z^3+27=(2z)^3+3^3\\\\=(2z+3)((2z)^2-2z\times 3+3^2)\\\\=(2z+3)(4z^2-6z+9)

Hence this is our required factor i.e.

8z^3+27=(2z+3)(4z^2-6z+9)


7 0
3 years ago
Read 2 more answers
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