<span>The congruency statement should be that which shows the congruency of the corresponding angle and the sides. In the rotation of the polygon, the angle A is congruent with angle A' still. The same is true for all the angles and sides. The congruency statement is therefore,
ABCD is congruent to A'B'C'D'
The answer to this item is letter A. </span>
We want to find the probability that the two students chosen for the duet are boys. We will find that the probability that both students chosen for the duet are boys is 0.458
If we assume that the selection is totally random, then all the students have the same<em> </em><em>probability </em><em>of being chosen.</em>
This means that, for the first place in the duet, the probability of randomly selecting a boy is equal to the quotient between the number of boys and the total number of students, this is:
P = 11/16
For the second member of the duet we compute the probability in the same way, but this time there is one student less and one boy less (because one was already selected).
Q = 10/15
The joint probability (so both of these events happen together) is just the product of the individual probabilities, this will give:
Probability = P*Q = (11/16)*(10/15) = 0.458
So the probability that both students chosen for the duet are boys is 0.458
If you want to learn more, you can read:
brainly.com/question/1349408
Answer:
11307.19 rounded and exact is 11307.1875
Step-by-step explanation:
Answer:
19/72
Step-by-step explanation:
To calculate the probability that a randomly-chosen child from this group likes either Chess or Swimming but not Football?
We already know the number that liked chess only which is 10, we have to solve for those that liked swimming only which is
8+7+16+x = 40
x which represent swimming only is
40-31 = 9
Thus probability = 10/72 + 9/72 = 19/72
The center is at origin O(0,0).
If it contains the point, P(-8,6), then the radius r is, by Pythagoras theorem,
r=sqrt((-8)^2+6^2)=10
The general equation of a circle at centre (xc,yc) with radius r is given by
(x-xc)^2+(y-yc)^2=r^2
Substituting r=10, (xc,yc)=(0,0)
the resulting equation is therefore
(x-0)^2+(y-0)^2=10^2
or simply
x^2+y^2=100
