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olga nikolaevna [1]

3 years ago

9

PLEASE HELP NOW THIS IS DUE REALLY SOON ILL MAKE YOU BRAINLIEST IF YOU CAN ANSWER NOW

1 answer:

Lynna [10]3 years ago

6 0

Angles 6 and 7, because they are alternate along the transversal.

Also angles 1 and 4.

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andreyandreev [35.5K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

1

$A_1 = 67.58 \ in^2$

2

$A_2 =415.4 \ ft^2$

3

$A_3 = 8.48 \ cm^2$

4

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Step-by-step explanation:

Generally the area of a sector is mathematically represented as

$A = \frac{\theta}{360} * \pi r^2$

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Now at $r_2 = 20 ft$ in and $\theta_2 = 119 ^o$

$A_2 = \frac{119}{360} * 3.142 * 20^2$

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$A_3 = \frac{23}{360} * 3.142 * 6.5 ^2$

$A_3 = 8.48 \ cm^2$

Now at $r_4 = 14.2 m$ and $\theta_4 = 360 -87 = 273 ^o$

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Wouldn’t it just be 3 units ?

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