Answer:
Step-by-step explanation:
Let the first number = x
Let the second number = x + 9
Let the third number = 4x
Together they make 123
x + x + 9 + 4x = 123 combine the left
6x + 9 = 123 Subtract 9 from both sides
6x = 123 - 9
6x = 114 Divide by 6
x = 114/6
x = 19
=================
First number = 19
Second number = 19 + 9 = 28
Third number = 4*19 = 76
Answer:
![x^{2} + 3x^{3} + 4x^{2} - 6x + 5](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B%203x%5E%7B3%7D%20%2B%204x%5E%7B2%7D%20-%206x%20%2B%205)
Step-by-step explanation:
first remove the parentheses
then add the like terms
lastly reorder the terms
9 is the answer for that problem
Given that a parking lot contains 100 cars, k of which happen to be lemons.
This is a conditional probability question.
Let event A be that a car is tested and event B be that a car is lemon.
The probability that a car is lemon is given by
![\frac{k}{100}](https://tex.z-dn.net/?f=%5Cfrac%7Bk%7D%7B100%7D)
The probability that a car is tested is given by
![\frac{m}{100}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7B100%7D)
The probability that a car is lemon and it is tested is given by
![\frac{n}{m}](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7Bm%7D)
For a conditional probability, the probablility of event A given event B is given by:
![P(A|B)= \frac{P(A\cap B)}{P(B)}](https://tex.z-dn.net/?f=P%28A%7CB%29%3D%20%5Cfrac%7BP%28A%5Ccap%20B%29%7D%7BP%28B%29%7D%20)
Therefore, the probability that a car is lemon, given that it is tested is given by.