Answer:
x = 1
Step-by-step explanation:
Given the matrix;
![-2\left[\begin{array}{ccc}x&-1\\3&5\end{array}\right] + \left[\begin{array}{ccc}3&8\\-1&6\end{array}\right] = \left[\begin{array}{ccc}x&10\\-7&-4\end{array}\right]](https://tex.z-dn.net/?f=-2%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%26-1%5C%5C3%265%5Cend%7Barray%7D%5Cright%5D%20%2B%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%268%5C%5C-1%266%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%2610%5C%5C-7%26-4%5Cend%7Barray%7D%5Cright%5D)
Converting to equations
From the first row of each matrices
-2x + 3 = x
Collect the like terms
-2x - x = -3
-3x = -3
x = -3/-3
x = 1
Hence the value of x is 1
105 - 75 = 30 That should do it.
Answer:
B 20r
Step-by-step explanation:
r² + + 100
r² = (r ) ( ) signs are all positive. 100 = (10) (10) last number. so
(r + 10)(r + 10)
r(r+ 10) + 10(r + 10)
r² + 10r + 10r + 100
r² + 20r + 100
The answer to this division question is 21