Answer:
B. f(g(x)) = -10x + 8
Step-by-step explanation:
When evaluating f(g(x)), substitute what g(x) is in place of g(x).
So instead of
f(g(x))
the function would be:
f(-5x + 6).
Now all you have to do is evaluate this.
To evaluate this function, substitute the value inside the f(x) for all instances of x in the equation.
f(x) = 2x - 4
f(-5x + 6) = 2(-5x + 6) - 4
f(-5x + 6) = -10x + 12 - 4
f(-5x + 6) = -10x + 8
Therefore, f(g(x)) = -10x + 8.
Answer:
<CBE and <BED are co-interior Angles. Let <BEC
= X 60+(×40)=180
× =80
Answer: ![\bold{(A): g=\dfrac{\sqrt{15}}{2},\quad h=\dfrac{\sqrt{5}}{2}}](https://tex.z-dn.net/?f=%5Cbold%7B%28A%29%3A%20g%3D%5Cdfrac%7B%5Csqrt%7B15%7D%7D%7B2%7D%2C%5Cquad%20h%3D%5Cdfrac%7B%5Csqrt%7B5%7D%7D%7B2%7D%7D)
<u>Step-by-step explanation:</u>
This is a special triangle because the side lengths have the following relationship:
30° ⇄ side length "a" <em>represented as "h" in your picture</em>
60° ⇄ side length "a√3" <em>represented as "g" in your picture</em>
90° ⇄ side length "2a" <em>represented as "√5" in your picture</em>
<u>Step 1: solve for "a" </u> <em>hypotenuse (2a) is given as √5</em>
![2a=\sqrt{5}](https://tex.z-dn.net/?f=2a%3D%5Csqrt%7B5%7D)
![a=\dfrac{\sqrt{5}}{2}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7B%5Csqrt%7B5%7D%7D%7B2%7D)
According to your picture, a = h, so ![h=\dfrac{\sqrt{5}}{2}](https://tex.z-dn.net/?f=h%3D%5Cdfrac%7B%5Csqrt%7B5%7D%7D%7B2%7D)
<u>Step 2: use the a-value from Step 1 to solve for the remaining side</u>
![g=a\sqrt{3}](https://tex.z-dn.net/?f=g%3Da%5Csqrt%7B3%7D)
![=\bigg( \dfrac{\sqrt{5}}{2}\bigg)\sqrt{3}](https://tex.z-dn.net/?f=%3D%5Cbigg%28%20%5Cdfrac%7B%5Csqrt%7B5%7D%7D%7B2%7D%5Cbigg%29%5Csqrt%7B3%7D)
![=\dfrac{\sqrt{15}}{2}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B%5Csqrt%7B15%7D%7D%7B2%7D)
The answer is 19m^2 , 333m^2 , 129m^2 , 32m^2
Answer:
113.85
Step-by-step explanation:
Area = (pi)r^2
(6.02)^2 times pi
36.2404pi
113.8525