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MatroZZZ [7]
2 years ago
15

The left-hand "tail" of the standard normal curve can be defined as the part of it that lies at least two standard deviations to

the left of the mean.
According to the Empirical Rule, approximately what percentage of the area under the whole curve is in the left-hand tail? Round your answer to the nearest tenth.
Mathematics
2 answers:
Leni [432]2 years ago
6 0
Roughly 95% of the data lies within 2 standard deviations of the mean. 

So (100% - 95%)/2 = 2.5% of the data lies within each tail.

This means roughly 2.5% of the data is in the left hand tail. 
Jobisdone [24]2 years ago
5 0

Answer:

2.5%

Step-by-step explanation:

The Empirical Rule states that 95% of the values lies between two standard deviations to the left of the mean and two standard deviations to the right of the mean. 50% of the values lies on the left side respect to the mean; so, 95%/2 = 47.5% of the values lies in the region formed two standard deviations to the left of the mean. In consequence, 50% - 47.5% = 2.5% of the values lies on the left-hand "tail" of the standard normal curve.  

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In total there are 25 students in the class.

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Sandy is working with a carpenter to frame a house. They are using8 -foot-long boards, but each board must be cut to be 7feet,10
faust18 [17]

Answer:

1 1/4 inches

5/48 foot

Step-by-step explanation:

to solve this question, convert feet to inches

1 feet = 12 inches

8 x 12 = 96 inches

7feet,10 3/4 inches long = (7 x 12) + 10 3/4 inches = 94 3/4 inches

Subtract  94 3/4 inches from 96 inches

96 inches -  94 3/4 inches = 1 1/4 inches

or 5/4 x 1/12 = 5/48 foot

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matrenka [14]

Answer:

42

Step-by-step explanation:

So are is length times width,

since we are dealing with a square, then the length and the width are congruent

so we can say that, for this case:

a = length * length

hence

196 = length^2

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8 0
3 years ago
If ε = {whole numbers less than 50 but greater than 20} and X = {perfect squares}, Y = {factors of 12}, Z = {prime numbers}; fin
Zigmanuir [339]

Answer:

A. X∪Y = {25, 36, 49}

B. X∩Y = ∅ i.e empty set

C. X' = {21, 22, 23, 24, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48}

D. X′∩Y∩Z = ∅

Step-by-step explanation:

We'll begin by determining the universal set (ε), set X, set Y and set Z.

This can be obtained as follow:

ε = {whole numbers less than 50 but greater than 20}

ε = {21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49}

X = {perfect squares}

X = {25, 36, 49}

Y = {factors of 12}

Y = ∅ i.e empty

Z = {prime numbers}

Z = {23, 29, 31, 37, 41, 43, 47}

A. Determination of X∪Y

X = {25, 36, 49}

Y = ∅

X∪Y =?

X∪Y => combination of elements in set X and Y without repeating any element in both X and Y.

X∪Y = {25, 36, 49}

B. Determination of X∩Y

X = {25, 36, 49}

Y = ∅

X∩Y =?

X∩Y => elements common to both set X and Y

X∩Y = ∅ i.e empty

C. Determination of X′

ε = {21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49}

X = {25, 36, 49}

X' =?

X' => elements in the universal set but not found in set X.

X' = {21, 22, 23, 24, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48}

D. Determination of X′∩Y∩Z

X' = {21, 22, 23, 24, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48}

Y = ∅

Z = {23, 29, 31, 37, 41, 43, 47}

X′∩Y∩Z =?

X′∩Y∩Z => elements common to set X', Y and Z

X′∩Y∩Z = ∅

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