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MatroZZZ [7]
3 years ago
15

The left-hand "tail" of the standard normal curve can be defined as the part of it that lies at least two standard deviations to

the left of the mean.
According to the Empirical Rule, approximately what percentage of the area under the whole curve is in the left-hand tail? Round your answer to the nearest tenth.
Mathematics
2 answers:
Leni [432]3 years ago
6 0
Roughly 95% of the data lies within 2 standard deviations of the mean. 

So (100% - 95%)/2 = 2.5% of the data lies within each tail.

This means roughly 2.5% of the data is in the left hand tail. 
Jobisdone [24]3 years ago
5 0

Answer:

2.5%

Step-by-step explanation:

The Empirical Rule states that 95% of the values lies between two standard deviations to the left of the mean and two standard deviations to the right of the mean. 50% of the values lies on the left side respect to the mean; so, 95%/2 = 47.5% of the values lies in the region formed two standard deviations to the left of the mean. In consequence, 50% - 47.5% = 2.5% of the values lies on the left-hand "tail" of the standard normal curve.  

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Solve the equation. Write a justification for each step. <br>5m-3=22
balu736 [363]

Answer:

m=5

Step-by-step explanation:

5m-3=22

  1. take 3 the other side by doing the opposite operation

5m= 22+3

5m= 25

  • then divide it by 5 on both sides to get the value of m.
  • 5m÷5=25÷5
  • 5and 5 cancels out and the answer becomes :

m=5

5 0
3 years ago
Read 2 more answers
1.- What type of parabola is this?
xz_007 [3.2K]

Answer:

<u>Part 1</u>

<u>Sideways or "horizontal" parabola</u> with a horizontal axis of symmetry.

<u>Part 2</u>

The vertex is the turning point:  (-3, 1)

<u>Part 3</u>

Vertex form of a horizontal parabola:

x=a(y-k)^2+h    

where:

  • (h, k) is the vertex
  • a is some constant
    If a > 0 the parabola opens to the right.
    If a < 0 the parabola opens to the left.

Point on the curve:  (-1, 2)

Substituting the vertex and the found point into the formula and solving for a:

\implies -1=a(2-1)^2-3

\implies -1=a-3

\implies a=2

<u>Part 4</u>

Equation for the given parabola in vertex form:

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Equation in standard form:

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4 0
2 years ago
The graph of f(x) = 24x^2 + 63x +34/ 4x + 3 has an oblique asymptote at y =
g100num [7]

<em>Correct answer is C). 6X+11</em>

Step-by-step explanation:

The given function f(x)= \frac{24x^{2} +63x + 34 }{4x+3}

On simplying the function f(x),

f(x)= \frac{6x(4x+3) -18x +63x + 34 }{4x+3}

f(x)= \frac{6x(4x+3) +45x + 34}{4x+3}

f(x)= \frac{6x(4x+3) +11(4x+3)+x-33 + 34 }{4x+3}

f(x)= \frac{6x(4x+3) +11(4x+3)+x+1}{4x+3}

f(x)=(6x+11)+\frac{(x+1)}{4x+3}

From above equation

"(6x+11)" is Oblique asymptote and \frac{(x+1)}{4x+3} is vertical asymptote

Therefore, Correct answer is C). 6X+11

8 0
3 years ago
Read 2 more answers
Pls help this is due soon check 2 that apply
dem82 [27]

Answer:

I am pretty sure it is option a and c

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3 0
3 years ago
Pay to Park
iragen [17]

Answer:

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Step-by-step explanation:

7 0
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