Answer:
They are so small that they barely make up any of the mass of the atom, and they are so miniscule that during Rutherford 's Gold foil experiment ,they didn't even react with the alpha particles. They circle the nucleus on a ring. shown through Rutherford Atomic Model
hope it helps you
Answer:
Determining flammability can be as simple as holding a sample of the substance over a match. If it burns, it is flammable, leading to additional experiments to find more properties. Measuring the heat given off by the substance when it burns gives the heat of combustion.
Explanation:
Answer:
1.27 atm.
Explanation:
The following data were obtained from the question:
Pressure (P) in torr = 968 torr
Pressure (P) in atm =...?
Thus, we can convert from torr to atm by doing the following:
Recall:
760 torr = 1 atm
Therefore,
968 torr = 968/760 = 1.27 atm
Therefore, 968 torr is equivalent to 1.27 atm.
Answer:
a) 2 (H+) ions
b) 1 (SO3²-) ions
c) 1.36 × 10^-22 grams.
Explanation:
According to this question, sulfurous acid has a chemical formula; H2SO3. It is made up of hydrogen and sulfite ion. Hydrogen ion (H+) is the cation while sulfite ion (SO32-) is the anion.
Based on the chemical formula, there are 2 moles of hydrogen ions that reacts with 1 mole of sulfite ion as follows:
2H+ + SO3²- → H2SO3
Hence;
- there are 2 hydrogen ions (2H+) present in H2SO3.
- there is 1 sulfite ion (SO3²-) present in H2SO3.
c) The mass of one formula unit of H2SO3 is calculated thus:
= 1.008 (2) + 32.065 + 15.999(3)
= 2.016 + 32.065 + 47.997
= 82.08 a.m.u
Since, 1 gram is = 6.02 x 10^23 a.m.u
82.08 a.m.u = 82.08/6.02 × 10^-23
= 13.6 × 10^-23
= 1.36 × 10^-22 grams.
The correct answer is B. Low chemical reactivity