All categories

3 years ago

What mass in grams of SO2 is needed to react with 37.50 mol of Oz?

Chemistry

1 answer:

-BARSIC- [3]3 years ago

6 0

Answer:

4804.5 g of SO₂ are needed to the reaction

Explanation:

The reaction to produce sulfuric acid is:

2SO₂ + O₂ + 2H₂O → 2H₂SO₄

Ratio is 1:2. 1 mol of oxygen needs 2 moles of sulfur dioxide in order to react. We can propose this rule of three.

If 1 mol of O₂ react to 2 moles of SO₂

Then, 37.50 moles of O₂ will react with (37.5 . 2) /1 = 75 moles of SO₂

We convert the moles to mass, to know the answer:

75 mol . 64.06 g / 1 mol = 4804.5 g of SO₂

You might be interested in

The rate constant for a certain reaction is measured at two different temperatures:

Talja [164]

Answer: The activation energy Ea for this reaction is 22689.8 J/mol

Explanation:

According to Arrhenius equation with change in temperature, the formula is as follows.

$ln \frac{k_{2}}{k_{1}} = \frac{-E_{a}}{R}[\frac{1}{T_{2}} - \frac{1}{T_{1}}]$

$k_1$ = rate constant at temperature $T_1$ = $2.3\times 10^8$

$k_2$ = rate constant at temperature $T_2$ = $4.8\times 10^8$

$E_a$ = activation energy = ?

R= gas constant = 8.314 J/kmol

$T_1$ = temperature = $280.0^0C=(273+280)=553K$

$T_2$ = temperature = $376.0^0C=(273+376)=649K$

Putting in the values ::

$ln \frac{4.8\times 10^8}{2.3\times 10^8} = \frac{-E_{a}}{8.314}[\frac{1}{649} - \frac{1}{553}]$

$E_a=22689.8J/mol$

The activation energy Ea for this reaction is 22689.8 J/mol

3 0

3 years ago

iron will react with oxygen to produce Fe2O3. how many grams of Fe2O3 will he produced if 0.18 mil of Fe reacts?

nasty-shy [4]

Answer:

14.4g

Explanation:

First, we need to write a balanced equation for the reaction between Fe and O2 to produce Fe2O3. This is illustrated below:

4Fe + 3O2 —> 2Fe2O3

From the balanced equation,

4moles of Fe produced 2moles of Fe2O3.

Therefore, 0.18mol of Fe will produce = (0.18x2) /4 = 0.09mol of Fe2O3.

Now we need to find the mass present in 0.09mol of Fe2O3. This can be achieved by doing the following:

Molar Mass of Fe2O3 = (56x2) + (16x3) = 112 + 48 = 160g/mol

Number of mole of Fe2O3 = 0.09mol

Number of mole = Mass /Molar Mass

Mass = number of mole x molar Mass

Mass of Fe2O3 = 0.09 x 160 = 14.4g

6 0

2 years ago

An analytical chemist weighs out 0.055g of an unknown triprotic acid into a 250mL volumetric flask and dilutes to the mark with

Katarina [22]

Answer:

Mass of the unknown acid is 4.0g

Explanation:

The determine the molar mass of the unknown acid, the steps below can be followed

Firstly, determine the concentration of the acid, the formula below can be used;

ConcA × Va/ConcB × Vb = Na/Nb

Where ConcA is the concentration of the unknown acid

ConcB is the concentration of the NaOH base

Va is the volume of acid and Vb is the volume of base

Since, the titration was said to have reached an equivalent point, it means the number of moles of the acid (Na) was equal to the number of moles of the base (Nb) and thus both will be assumed to be 1

Thus

ConcA × 250/0.13 × 6.6 = 1/1

ConcA = 0.13 × 6.6/250

ConcA = 0.003432M

Then, determine the actual number of moles (n) of the unknown acid used,

ConcA = no of moles of acid/volume of acid (in dm³ or L)

To convert mL to L, we divide by 1000

Hence, 250ml = 0.25L

0.003432 = n/0.25

n = 0.003432 × 0.25

n = 0.01373 moles

To determine the molar mass;

n = mass/molar mass

The mass was given in the question to be 0.055g

Thus

0.01373 = 0.055/molar mass

molar mass = 0.055/0.01373

molar mass = 4.0g

5 0

2 years ago

What is the empirical formula of a compound containing carbon, hydrogen, and oxygen in the ratio 14:42:84?

Alexxandr [17]

<h3>Answer:</h3>

D. CH₃O₆

<h3>Explanation:</h3>

We are given the ratio of carbon, hydrogen and oxygen in a compound as 14: 42 : 84

We are supposed to determine the empirical formula of the compound;

We need to know what is an empirical formula;

An empirical formula of a compound is a formula that shows the simplest whole number ratio of elements in a compound.

In this case;

The ratio of C : H : O is 14 : 42 : 84

Note, this is not the simplest ratio.

But we can simplify further to get the simplest whole number ratio;

Therefore, 14 : 42 : 84 is equal to 1 : 3 : 6

Thus, the simplest whole number ratio of C : H : O in the compound is 1 : 3 : 6

Therefore, the empirical formula of the compound is CH₃O₆

3 0

2 years ago

2. A transformer only works with which type of current?

Tems11 [23]

Answer:

C. Alternating

8 0

3 years ago

Read 2 more answers