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Ostrovityanka [42]
3 years ago
9

A cheetah runs at an average speed of 50 mph between two jungles that are 150 miles apart. An antelope runs at an average speed

of 30 mph, a lion runs at an average speed of 25 mph, and an elephant runs at an average speed of 15 mph. How long does it take each animal to run to the second jungle?
Mathematics
1 answer:
Assoli18 [71]3 years ago
8 0
Cheetah: 3 hours
Antelope: 5 hours
Lion: 6 hours
Elephant: 10 hours
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nevsk [136]
The answer is B.

A radius means a line which goes from center to a point on the circle. So every line that includes point A and ends on the circle is a radius.
3 0
3 years ago
What is the value of y in the equation 4(y-6) = - 4 ? REMEMBER TO DISTRIBUTE! *
Nezavi [6.7K]

Answer:

y = 5

Step-by-step explanation:

4 (y - 6) = -4

  ×4 ×4               Distribute 4 with y and 6

4y - 24 = -4

    +24    +24      Add 24 to both sides of the equation

4y = 20

÷4    ÷4               Divide each side by 4

y = 5

8 0
4 years ago
Read 2 more answers
In Exercises 51−56, the letters a, b, and c represent nonzero constants. Solve the equation for x
chubhunter [2.5K]

Answer:

x = 9b/C

Step-by-step explanation:

Cx – 4b = 5b

Add 4b to each side

Cx – 4b+4b = 5b+4b

Cx = 9b

Divide by C

Cx/C = 9b/C

x = 9b/C

8 0
3 years ago
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A recent survey of 1000 American women between the ages of 45 and 64 asked them what medical condition they most feared. Of thos
defon

Answer:

Confidence interval for the population proportion of women fearing from breast cancer are 61%

Step-by-step explanation:

Point estimate of the proportion of the population of women who feared from breast cancer is:

β=61%

Standard error of the estimate:

Se= 0.154

Margin of error for 90% confidence interval for the population proportion:

0.254

90% confidence interval for the population proportion will be

(0.5846,0.6354)

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4 years ago
A recent study revealed that the average weight of babies born in the United States is normally distributed with a mean of 7.5 p
Naddik [55]

Answer:

a. the standard deviation for young mothers is not expected to be different than the standard deviation in the population

Step-by-step explanation:

The population mean = μ= 7.5

Sample mean = x`= 7.3

Sample standard deviation= s= 0.6

Sample size = 87

Assuming normality we perform z test

z= x`-u/s/√n

z= 7.3-7.5/0.6/√87

z= -3.11

The critical region for 0.05 for two tailed test is z>+1.96 and Z<-1.96

Since the calculated z= -3.11 falls in the critical region Z<-1.96 we conclude that birth rate is lower in the young mothers.

a. the standard deviation for young mothers is not expected to be different than the standard deviation in the population

Only choice a is correct because when n > 30 the population standard deviation and the sample standard deviation are assumed to be normal

Choice b cannot be the correct option because it is already inferred that only one baby was measured per mother.

Choice C cannot be also the best choice because it is already assumed.

Choice d is totally incorrect.

7 0
3 years ago
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