8.625 is the correct answer.
Number of pennies:P
Number of nickels:N
Number of dollar bills:D
P=N+12
N=D+5
1P+5N+100D=996
^given
Therefore
P=(D+5)+12
P=D+17
Plug back into main equation
(D+17)+5(D+5)+100D=996
Combine like terms
106D+42=996
106D=954
D=954/106=9
9 Dollar bills
N=D+5
N=(9)+5=14
14 Nickels
P=N+12
P=(14)+12=26
26 Pennies
26*1+14*5+9*100=996
Final answer:
9 Dollars
14 Nickels
26 Pennies
The answer would be b, hope it helps!
A fleet of nine taxis is to be dispatched to three airports in such a way that three go to airport A, five go to airport B, and one goes to airport C. In how many distinct ways can this be accomplished?
2.44) Refer to Exercise 2.43. Assume that taxis are allocated to airports at random.
a) If exactly one of the taxis is in need of repair, what is the probability that it is dispatched to airport C?
b) If exactly three of the taxis are in need of repair, what is the probability that every airport receives one of the taxis requiring repairs?
So, my answer to 2.44a is 1/9. Hopefully this is correct at least :)
For 2.44b, my guess was
(3C1)(1/3)(2/3)2 * (5C1)(1/3)(2/3)4 * 1/3
The solutions manual on chegg (which seems to be riddled with errors) says something completely different. Is my calculation correct?
Answer:
in total she would spend 27.90 so she should bring C i got this by doing 7.80 x 3 because she is buying 3 medium pizzas then i did 0.75 x 6 and got 27.90 so at least bring 25-30 dollars with her
Step-by-step explanation:
