((x^2)(y^2) - 9) *(3 - xy).
Note difference of two squares: (a^2 - b^2) = (a-b)(a+b)
(x^2)(y^2) - 9 = (xy)^2 - 3 ^2 = (xy - 3)(xy + 3). (Take note)
(3- xy) = -(xy - 3). (Take note of this also)
Your question said: ((x^2)(y^2) - 9) times (3 - xy),
Don't you think it should be divide? Would solve it as divide.
((x^2)(y^2) - 9) /(3 - xy) = (xy - 3)(xy + 3) / -(xy - 3)
= -(xy + 3).
Answer is (3). Solved it as divide. Using times gives none of the solution among the options.
Cheers.
F(7)= -22 - 3(7) + 3
f(7)= -22 - 21 +3
f(7)= -40
Hope that helps!
Answer:
i thank 180 or 115×31=
Step-by-step explanation:
i am not sure sorry):
1/2 + 1/8 + 1/4 = CHANGE THE DENOMINATOR SO IT CAN BE EVEN
4/8 + 1/8 + 2/8 = FINAL ANSWER ....... 7/8
Answer:
49°
Step-by-step explanation:
arccos x = 15/23
