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2 years ago

which digit 1,634,677 has value this is greater than 10 times the value of the fight digit to its right

Mathematics

1 answer:

kirill115 [55]2 years ago

8 0

Answer:

The ones digit or the First 7 to the left

Step-by-step explanation:

Since 10 times more

so ones place is 7

Tens place is 70

hunreds place is 600

thousands is 4000

ten thousands is 30,000

hundred thousands is 600,000

Million’s digit is 1,000,000

So since the only one with a 10 times difference is 7

So 7

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Confused on this help plss

ValentinkaMS [17]

Answer:

of iv

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x+2({\color{#c92786}{4-x}})=2x+6-3x

x+2(4−x)=2x+6−3x

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Step-by-step explanation:

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8 0

2 years ago

1. write it on a piece of paper

stiv31 [10]

$\\ \sf\longmapsto 1\dfrac{1}{2}+2\dfrac{3}{4}$

$\\ \sf\longmapsto \dfrac{3}{2}+\dfrac{11}{4}$

$\\ \sf\longmapsto \dfrac{6+11}{4}$

$\\ \sf\longmapsto \dfrac{17}{4}$

2:-

$\\ \sf\longmapsto 4\dfrac{3}{7}+6\dfrac{1}{5}$

$\\ \sf\longmapsto \dfrac{31}{7}+\dfrac{31}{5}$

$\\ \sf\longmapsto \dfrac{155+225}{35}$

$\\ \sf\longmapsto \dfrac{380}{35}$

$\\ \sf\longmapsto 12$

3:-

$\\ \sf\longmapsto 4\dfrac{2}{5}+5\dfrac{2}{6}$

$\\ \sf\longmapsto \dfrac{22}{5}+\dfrac{32}{6}$

$\\ \sf\longmapsto \dfrac{132+160}{30}$

$\\ \sf\longmapsto \dfrac{292}{30}$

4:-

$\\ \sf\longmapsto 3\dfrac{7}{7}+3\dfrac{1}{3}$

$\\ \sf\longmapsto \dfrac{28}{7}+\dfrac{10}{3}$

$\\ \sf\longmapsto 4+\dfrac{10}{3}$

$\\ \sf\longmapsto \dfrac{12+10}{3}$

$\\ \sf\longmapsto \dfrac{22}{3}$

7 0

2 years ago

Read 2 more answers

Can anyone slove this question pls

skad [1K]

we have: -10/4 = -2.5 ⇒ -2 > -2.5 > -3

ANSWER : -2 and -3

ok done. Thank to me :>

4 0

2 years ago

Sin(a+b) + sin (a-b) = 2 sin a cos b verify the identitiy

Bas_tet [7]

Write out the sum formula for sin
sin(x + y) = sinxcos + sinycosx 

Then expand sin(a + b) + sin(a - b) 
sinacosb + sinbcosa + sinacosb - sinbcosa 
The 2nd and 4th terms cancel and you get 
2sinacosb

6 0

2 years ago

The members of the Student Activity Council on your campus are meeting to select three speakers for a month-long event celebrat

Komok [63]

The number of different ways that three speakers can be selected is 10 ways

Given the names of choice to be Ben, Will, Stewart, Hilary, and Kate. This means that we have a total of 5 name choices.

If the members of students activities are to select three speakers among these people, the number of ways this can be done is by using the combination rule as shown;

$nCr=\frac{n!}{(n-r)!r!}$

From the question, n = 5 and r = 3. On substituting

$5C3=\frac{5!}{(5-3)!3!}\\5C3=\frac{5!}{2!3!}\\5C3=\frac{5 \times 4 \times 3!}{2 \times 3!} \\5C3=\frac{20}{2}\\5C3 = 10 ways$

Hence the number of different ways that three speakers can be selected is 10 ways.

Learn more here: brainly.com/question/24145745

7 0

2 years ago