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const2013 [10]
3 years ago
10

Thanks in advance to all the people who provided support to my problem!

Mathematics
1 answer:
sashaice [31]3 years ago
5 0

Answer as an improper fraction:  7/4

Answer as a mixed number:  1 & 3/4

Answer in decimal form:  1.75

Each answer above is a different way to represent the same distance

=========================================

Explanation:

I'm assuming the total distance is 5&1/4. This converts to the improper fraction 21/4 through the use of the formula below

a & b/c = (a*c+b)/c

In this case, a = 5, b = 1 ,c = 4

If each leg of the race is x miles, then the three legs add to x+x+x = 3x miles total. Set this equal to 21/4 and solve for x

--------------------------

3x = 21/4

(1/3)*3x = (1/3)*(21/4)

x = (1*21)/(3*4)

x = (21/3)*(1/4)

x = 7*(1/4)

x = 7/4

-------------------------

Each leg is 7/4 miles. Lets convert this to a mixed number through long division.

7/4 = 1 remainder 3

The two results above indicate that 7/4 = 1 & 3/4

To help confirm this, imagine you had 7 slices of pie and 4 people to divide those 7 slices among. Each person will get 1 slice meaning there are 7-4 = 3 slices leftover, aka the remainder.

If you need the answer in decimal form, then 1 & 3/4 = 1 + 3/4 = 1+0.75 = 1.75

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6 0
3 years ago
Solve for x. −12x+13&gt;35 Drag and drop a number or symbol into each box to correctly complete the solution.
Katen [24]

Answer:

x < -11/6.

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3 years ago
Complete the assignment on a separate sheet of paper<br><br> Please attach pictures of your work.
Irina18 [472]

Answer:

<u>TO FIND :-</u>

  • Length of all missing sides.

<u>FORMULAES TO KNOW BEFORE SOLVING :-</u>

  • \sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}
  • \cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}
  • \tan \theta = \frac{Side \: opposite \: to \: \theta}{Side \: adjacent \: to \: \theta}

<u>SOLUTION :-</u>

1) θ = 16°

Length of side opposite to θ = 7

Hypotenuse = x

=> \sin 16 = \frac{7}{x}

=> \frac{7}{x} = 0.27563......

=> x = \frac{7}{0.27563....} = 25.39568..... ≈ 25.3

2) θ = 29°

Length of side opposite to θ = 6

Hypotenuse = x

=> \sin 29 = \frac{6}{x}

=> \frac{6}{x} = 0.48480......

=> x = \frac{6}{0.48480....} = 12.37599..... ≈ 12.3

3) θ = 30°

Length of side opposite to θ = x

Hypotenuse = 11

=> \sin 30 = \frac{x}{11}

=> \frac{x}{11} = 0.5

=> x = 0.5 \times 11 = 5.5

4) θ = 43°

Length of side adjacent to θ = x

Hypotenuse = 12

=> \cos 43 = \frac{x}{12}

=> \frac{x}{12} = 0.73135......

=> x = 12 \times 0.73135.... = 8.77624.... ≈ 8.8

5) θ = 55°

Length of side adjacent to θ = x

Hypotenuse = 6

=> \cos 55 = \frac{x}{6}

=> \frac{x}{6} = 0.57357......

=> x = 6 \times 0.57357.... = 3.44145.... ≈ 3.4

6) θ = 73°

Length of side adjacent to θ = 8

Hypotenuse = x

=> \cos 73 = \frac{8}{x}

=> \frac{8}{x} = 0.29237......

=> x = \frac{8}{0.29237.....} = 27.36242..... ≈ 27.3

7) θ = 69°

Length of side opposite to θ = 12

Length of side adjacent to θ = x

=> \tan 69 = \frac{12}{x}

=> \frac{12}{x} = 2.60508......

=> x = \frac{12}{2.60508....}  = 4.60636.... ≈ 4.6

8) θ = 20°

Length of side opposite to θ = 11

Length of side adjacent to θ = x

=> \tan 20 = \frac{11}{x}

=> \frac{11}{x} = 0.36397......

=> x = \frac{11}{0.36397....}  =30.22225.... ≈ 30.2

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Answer:

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Subtract 105° from both sides

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