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B because if there are 10 large dogs and that is two times the number of small dogs than there are half as many small dogs as big doge which would mean the equation is D=1/2(10)+10.
Answer:
B. b = 3a + 2
Step-by-step explanation:
We can write the equation in slope-intercept form as b = ma + c, where,
m = slope/rate of change
c = y-intercept/initial value
✔️Find m using any two given pair of values, say (2, 8) and (4, 14):
Rate of change (m) = change in b/change in a
m = (14 - 8)/(4 - 2)
m = 6/2
m = 3
✔️Find c by substituting (a, b) = (2, 8) and m = 3 into b = ma + c. Thus:
8 = 3(2) + c
8 = 6 + c
8 - 6 = c
2 = c
c = 2
✔️Write the equation by substituting m = 3 and c = 2 into b = ma + c. Thus:
b = 3a + 2
The missing exponent is 22
Answer:
G. ABD = 74
H. DBC = 206
I. XYW = 33.75
J. WYZ = 46.25
Step-by-step explanation:
For G and H: You have a straight line (ABC) with another line coming off of it, creating two angles (ABD and DBC). A straight line has an angle of 180 degrees. This means that the two angles from the straight line when combined will give you 180 degrees. Solve for x.
ABD + DBC = ABC
(1/2x + 20) + (2x - 10) = 180
1/2x + 20 + 2x - 10 = 180
5/2x + 10 = 180
5/2x = 170
x = 108
Now that you have x, you can solve for each angle.
ABD = 1/2x + 20
ABD = 1/2(108) + 20
ABD = 54 + 20
ABD = 74
DBC = 2x - 10
DBC = 2(108) - 10
DBC = 216 - 10
DBC = 206
For I and J: For these problems, you use the same concept as before. You have a right angle (XYZ) that has within it two other angles (XYW and WYZ). A right angle has 90 degrees. Combine the two unknown angles and set it equal to the right angle. Solve for x.
XYW + WYZ = XYZ
(1 1/4x - 10) + (3/4x + 20) = 90
1 1/4x - 10 + 3/4x + 20 = 90
2x + 20 = 90
2x = 70
x = 35
Plug x into the angle values and solve.
XYW = 1 1/4x - 10
XYW = 1 1/4(35) - 10
XYW = 43.75 - 10
XYW = 33.75
WYZ = 3/4x + 20
WYZ = 3/4(35) + 20
WYZ = 26.25 + 20
WYZ = 46.25
