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Ann [662]
2 years ago
5

Which is the graph of the linear equality 2x-3y<12

Mathematics
1 answer:
WINSTONCH [101]2 years ago
7 0

Answer:

The graph below shows the answer to

2x - 3y < 12

Also shown as

-3y < -2x + 12

Step-by-step explanation:

You can rearrange the inequality by subtracting 2x from both sides to isolate the y.

You now have -3y < 12 -2x

which can be put into the standard linear equation form of

-3y < -2x + 12

Then you divide both sides by -3 to get singular value of y, which is something like

-3/-3y < -2/-3x + 12/-3

which is

y > 2/3x -4

Note: I switched direction of the inequality because you are dividing both sides by a negative value.

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The answer would be y=32/11
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3 years ago
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The graph of f(x) = x2 is translated to form g(x) = (x – 5)2 + 1. On a coordinate plane, a parabola, labeled f of x, opens up. I
Firdavs [7]

The <em>quadratic</em> function g(x) = (x - 5)² + 1 passes through the points (2, 10) and (8, 10) and has a vertex at (5, 1).

<h3>How to analyze quadratic equations</h3>

In this question we have a graph of a <em>quadratic</em> equation translated to another place of a <em>Cartesian</em> plane, whose form coincides with the <em>vertex</em> form of the equation of the parabola, whose form is:

g(x) = C · (x - h)² - k     (1)

Where:

  • (h, k) - Vertex coordinates
  • C - Vertex constant

By direct comparison we notice that (h, k) = (5, 1) and C = 1. Now we proceed to check if the points (x, y) = (2, 10) and (x, y) = (8, 10) belong to the parabola.

x = 2

g(2) = (2 - 5)² + 1

g(2) = 10

x = 8

g(8) = (8 - 5)² + 1

g(8) = 10

The <em>quadratic</em> function g(x) = (x - 5)² + 1 passes through the points (2, 10) and (8, 10) and has a vertex at (5, 1).

To learn more on parabolae: brainly.com/question/21685473

#SPJ1

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2 years ago
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Of you have 3 squared you get 9 then 2 times -2 is -4. then you add them 9=-4 which would be ...A: 5
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3 years ago
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(-3,2) and ( 2,-13) slope intercept equation
Georgia [21]

Given:

The points are (-3, 2) and (2, -13).

To find:

Slope-intercept form of the equation.

Solution:

Here x_1=-3, y_1=2, x_2=2, y_2=-13.

Slope of the line:

$m=\frac{y_2-y_1}{x_2-x_1}

$m=\frac{-13-2}{2-(-3)}

$m=\frac{-15}{5}

m = -3

Using point-slope formula:

y-y_1=m(x-x_1)

y-2=-3(x-(-3))

y-2=-3(x+3)

y-2=-3x-9

Add 2 on both sides.

y-2+2=-3x-9+2

y=-3x-7

Slope-intercept form of the equation is y = -3x - 7.

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9m
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