Which is the graph of the linear equality 2x-3y<12
1 answer:
Answer:
The graph below shows the answer to
2x - 3y < 12
Also shown as
-3y < -2x + 12
Step-by-step explanation:
You can rearrange the inequality by subtracting 2x from both sides to isolate the y.
You now have -3y < 12 -2x
which can be put into the standard linear equation form of
-3y < -2x + 12
Then you divide both sides by -3 to get singular value of y, which is something like
-3/-3y < -2/-3x + 12/-3
which is
y > 2/3x -4
Note: I switched direction of the inequality because you are dividing both sides by a negative value.
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Answer:
(a) There are asymptotes at x=3/2 and x=-1/3
Step-by-step explanation:
The denominator zeros can be found by factoring:
f(x) = (x +1)/((2x -3)(3x +1))
Neither of the denominator factors is cancelled by the numerator factor, so each represents a vertical asyptote, not a function hole.
The asymptotes are at the values of x where the denominator is zero:
2x -3 = 0 ⇒ x = 3/2
3x +1 = 0 ⇒ x = -1/3
