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3 years ago

How many moles are in 60.0 grams of water?

Chemistry

1 answer:

Mashutka [201]3 years ago

5 0

<h3>Answer:</h3>

3.33 mol H₂O

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

60.0 g H₂O (Water)

<u>Step 2: Identify Conversions</u>

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

<u>Step 3: Convert</u>

Set up: $\displaystyle 60.0 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O})$
Multiply: $\displaystyle 3.32963 \ mol \ H_2O$

<u>Step 4: Convert</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

3.32963 mol H₂O ≈ 3.33 mol H₂O

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4 years ago

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Answer:

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Explanation:

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2 years ago

If we compare a mole of carbon atoms to a mole of oxygen atoms, which sample will contain more atoms?.

Alex Ar [27]

Since 1 mole of any element contains 6.0221023 atoms, a mole of carbon and a mole of oxygen will have the same number of atoms.

<h3>Is a mole of oxygen equivalent to a mole of carbon?</h3>

Answer and justification The molar mass of carbon differs from the molar mass of oxygen, hence this assertion is untrue. As a result, one mole of oxygen and one mole of carbon cannot have the same mass.

<h3>What kind of link unites carbon and oxygen?</h3>

A polar covalent link between carbon and oxygen is known as a carbon-oxygen bond. With six valence electrons, oxygen likes to either share two of them in a bond with carbon, leaving the remaining four unoccupied.

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1 year ago

Which conversion factor do you use first to calculate the number of grams of CO 2 produced by the reaction of 50.6 g of CH 4 wit

Brilliant_brown [7]

Answer:

Thus, first conversion of mass of methane into moles by dividing it with 16.04 g/mol

Mass = 138.63 g

Explanation:

The balanced chemical reaction is shown below:-

$CH_4+2O_2\rightarrow CO_2+2H_2O$

Firstly the moles of methane gas reacted must be calculate as:-

Given, mass of methane = 50.6 g

Molar mass of methane gas = 16.04 g/mol

The formula for the calculation of moles is:-

$Moles=\frac{Mass\ taken}{Molar\ mass}=\frac{50.6}{16.04}\ mol=3.15\ mol$

Thus, from the reaction stoichiometry,

1 mole of methane produces 1 mole of carbon dioxide

Also,

3.15 mole of methane produces 3.15 mole of carbon dioxide

Moles of $CO_2$ = 3.15 mole

Molar mass of $CO_2$ = 44.01 g/mol

Mass = Moles*Molar mass = $3.15\times 44.01$ g = 138.63 g

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