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lisabon 2012 [21]
3 years ago
14

a culinary club earns $1360 from a dinner service. they sold 45 adult meals and 80 student meals. an adult meal costs twice as m

uch as a student meal. what is the cost of an adult meal?
Mathematics
1 answer:
meriva3 years ago
4 0

Answer: total cost earn=$1360

adult sold =45

student sold =80

adult cost twice as student cost so we can say adult sold 45+45=90

so total sold=90+80=170  

to get the cost of 1 meal we divide 1360 by 170

1360/170=8

one student meal cost=8$

one adult meal cost=8*2=16

total students meal cost=8*80=640$

total adult meal cost=16*45=720

640+720=1360


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Stephanie goes shopping on Sunday, she has $60. After buying 20 chocolates, she has $10 left. How much did the chocolate cost?
m_a_m_a [10]

Answer: x=2.5


Step-by-step explanation:

First we need to set up and equation

10= 60 - 20x

where x is the amount the cookies cost

subtract 60 from both sides

-50=- 20x

now divide each side by 20 so hat we can isolate the x

-50/-20= x

x= 2.5

now to check just multiply it by 20 then subtract from 60.

2.5 x 10= 50

60-50=10


6 0
3 years ago
Read 2 more answers
What is the answer need it
denis-greek [22]

Answer:

\frac{7}{10} |

Step-by-step explanation:

STEP 1:

2/3 + 7/10 = ?

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(2/3, 7/10) = 30

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

(\frac{2}{3} * \frac{10}{10}) + (\frac{7}{10} * \frac{3}{3}) = ?

Complete the multiplication and the equation becomes

\frac{20}{30} + \frac{21}{30}

The two fractions now have like denominators so you can add the numerators.

Then:

\frac{20+21}{30} = \frac{41}{30}

This fraction cannot be reduced.

The fraction 41/30

is the same as

41 divided by 30

Convert to a mixed number using

long division for 41 ÷ 30 = 1R11, so

41/30 = 1 11/30

Therefore:

2/3+7/10= 1 11/30

STEP 2:

41/30 + -2/3

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(41/30, -2/3) = 30

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

(\frac{41}{30} *\frac{1}{1} ) + ( \frac{-2}{3} * \frac{10}{10} )

The two fractions now have like denominators so you can add the numerators.

Then:

\frac{41+-20}{30} = \frac{21}{30}

This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 21 and 30 using

GCF(21,30) = 3

\frac{21/3}{30/3} =\frac{7}{10}

Therefore:

\frac{41}{30} + \frac{-2}{3} =\frac{7}{10}|

8 0
2 years ago
if a quadratic equation with real coefficients has a discriminant of -36 then what type of roots does it have
Aleks04 [339]

Step-by-step explanation:

We have,

If a quadratic equation with real coefficients has a discriminant of -36.

The general form of quadratic equation is :

ax^2+bx+c=0

The discriminant of this equation is : D=b^2-4ac

If D=0, it will have 1 real roots

If D>0, it will have 2 real roots

If D<0, it will have no real roots

We have,

D = -36 < 0, so, the quadratic equation will have no real roots.

5 0
3 years ago
-39.85 + 34.8 - .375
Monica [59]
I believe it is -5.425
8 0
2 years ago
Read 2 more answers
The owner of a small pet supply store wants to open a second store in another city, but he only wants to do so if more than one-
Andrei [34K]

Answer:

The answer is "The null hypothesis was rejected".

Step-by-step explanation:

Following are the right-tailed test:

Calculating the null and alternative hypothesis:

H_0 : p = 0.3333\\\\H_a : p > 0.3333\\\\n = 150\\\\x = 64\\\\\hat{p} = \frac{x}{n} = \frac{64}{150} = 0.4267\\\\P_0 = 0.3333\\\\1 - P_0 = 1 - 0.3333 = 0.6667\\\\

z = \frac{\hat{p} - P_0}{[\sqrt{\frac{P_0 \times (1 - P_0 )}{n}}]}

   = \frac{0.4267 - 0.3333}{[\sqrt{\frac{(0.3333 \times 0.6667)}{150}}]}\\\\= 2.426

Calculating the right-tailed test:

P(z > 2.426) = 1 - P(z < 2.426) = 1 - 0.9924 = 0.0076\\\\P-value = 0.0076\\\\\alpha = 0.05\\\\P-value < \alpha

Therefore, we reject the null hypothesis.

This example shows that more than a third of the families own pets in this town.

5 0
2 years ago
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