1answer.
Меню
Ask question
Login
Signup
Ask question
Menu
All categories
English
Mathematics
Social Studies
Business
History
Health
Geography
Biology
Physics
Chemistry
Computers and Technology
Arts
World Languages
Spanish
French
German
Advanced Placement (AP)
SAT
Medicine
Law
Engineering
miv72
[106K]
3 years ago
13
You roll a fair 6-sided die. What is P(roll a 2)
Mathematics
Answer
Comment
Send
1
answer:
svp
[43]
3 years ago
4
0
What are u looking for? if ur looking for 2 only then it will be 1/6 which equals to .16
Send
You might be interested in
What is 1000000×9230997
Triss [41]
9.230997e+12
hope this helped
3
0
3 years ago
Read 2 more answers
The art club had an election to select a president. 25% of the 80 members of the club voted in the election. How many members vo
Alina [70]
Answer:
20, the answer is 20 members
3
0
3 years ago
Read 2 more answers
What is the <br> mean,median,mode and range with the outlier 44?
il63 [147K]
Answer:
hello
Step-by-step explanation:
4
0
3 years ago
Rations
Ray Of Light [21]
What?wait a minute I think it’s 365
6
0
3 years ago
What is the common denominator for 1/2 and 1/4
liubo4ka [24]
4 you multiply 2 times two to get four as your denominator so it would be 2/4 &1/4
4
0
3 years ago
Read 2 more answers
Other questions:
What is the missing factor in the equation
10
·
2 answers
The square root of 73
12
·
1 answer
The function h is defined by h(x)=x^2 +2.<br> Find h(3y).
5
·
1 answer
Square is not rhombus
9
·
1 answer
Solve the equation 4.8x+13=1
5
·
1 answer
What numbers should be added to -5/6 so as to get -3/2
6
·
1 answer
EASY QUESTIONS FOR EASY POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!
8
·
1 answer
Pam's age is 3 times din<br> age the sum of the<br> ages is 32. What<br> Jim's age?
12
·
1 answer
43x+ 67y = -24 and 67x + 43y = 24 solve
11
·
1 answer
Given the function:<br> f(x) = x² + 7<br> =<br> Find the value of f(-4).
7
·
1 answer
×
Add answer
Send
×
Login
E-mail
Password
Remember me
Login
Not registered?
Fast signup
×
Signup
Your nickname
E-mail
Password
Signup
close
Login
Signup
Ask question!