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maksim [4K]
3 years ago
6

The process of providing only the essentials and hiding the details is known as _____. a. algorithm b. data structure c. abstrac

tion d. optimization
Computers and Technology
1 answer:
adoni [48]3 years ago
3 0
The answer is (data) abstraction!
Hope it helped (:
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Please choose the correct answer please tell fast​
pav-90 [236]

Answer:

the answer might be 2......

7 0
3 years ago
The purpose of an Internet _____ is to receive packets and send them along towards their final destination.
Bumek [7]

The tool that receives packets and send them along towards their final destination is; Internet Server

<h3>Internet Servers</h3>

We are told that the tool is used to receive packets and send them along towards their final destination.

  • Now, the tool is an internet server because internet servers are softwares and hardwares that make use of HTTP and other protocols to respond to client requests that are made over the World Wide Web.

Now, the main job of an internet server is to display website content through storing, processing and delivering webpages to the final destination.

Read more about internet server at; brainly.com/question/20602197

7 0
2 years ago
To achieve the maximum confidentiality and integrity found in a completely secure information system would require that the syst
fgiga [73]

Answer:

The answer is "Option a".

Explanation:

Privacy is a set of rules, which limiting access to the data, and integrity ensures impartiality, accuracy, and reliability is assured to ensure, which authorized persons can have secure access to the data.

The system needs no access for everyone to achieve its secrecy and integrity contained in a completely safe data system, that's why the given statement is "true".

5 0
3 years ago
The following code does not work as intended. It is meant to input two test grades and return the average in decimal format:
vredina [299]

Answer:

Type casting error

Explanation:

Logically, the program is correct and it is expected to return the average value. However, test1 and test2 are int values and when you applies any algebraic expression on Int, it will result into Int.

So, in this part (test1 + test2 )/2, two integers are adding and the final result is still an integer and this part will act as an integer even if you multiple or divide with any external number.

For example,

test1 = 4

test2 = 5

test1 + test2 = 9

Now, if you divide it by 2, it will still react as an integer portion. So, 9/2 would result in 4 instead of 4.5. All the calculation is done on the right side before assigning it to a double variable. Therefore, the double variable is still getting the int value and your program is not working correctly.

The solution is to typecast the "(test1 + test2 )/2" portion to double using Double.valueOf(test1 + test2)/2 ;

I have also attached the working code below.

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

 System.out.println("Hello World");

 Scanner scan = new Scanner (System.in);

 int test1 = scan.nextInt();

       int test2 = scan.nextInt();

       double average = Double.valueOf(test1 + test2)/2 ;

       System.out.println("Answer: " + average);

}

}

4 0
3 years ago
What could be one possible reason where the recipient is not guaranteed that the data being streamed will not get interrupted?
anyanavicka [17]

Answer

The senders PC is using UDP protocol

Explanation

UDP is the User Datagram Protocol which is used as an alternative communication protocol to the TCP which is used primarily for establishing low latency and loss of tolerating connections between applications on the internet UDP is normally used by the programs running on different computers on a network. Its purposes is to send short messages which are datagrams. It is not much reliable because of its occasional loss of packet. Due to this packet loss  the recipient is not guaranteed that the data being streamed will not get interrupted. This is because If a router on the Internet starts getting overloaded, or a packet gets corrupted due to interference or anything, the packet will be dropped unlike the TCP (Transmission control  protocol)which resend the packets and keeps re sending. The UDP does not resend the packets which are dropped. Once they are dropped that all.


3 0
3 years ago
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