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Angelina_Jolie [31]
3 years ago
5

A specialized output device for producing charts, maps, and very high-quality drawings is

Computers and Technology
1 answer:
Nimfa-mama [501]3 years ago
3 0

Answer:

B- plotter

Explanation:

because it's designed to produce high quality graphics.

You might be interested in
In a linked chain implementation of a queue, the performance of the enqueue operation
alexdok [17]

Answer:

A.O(1)

Explanation:

In the implementation of queue by using linked chain the performance of  the enqueue operation is O(1).We have to  maintain  two pointers one  head and the other tailand  for  enqueue operation  we have to insert element  to the next of the tail and then  make that element  tail.Which takes O(1) time.

4 0
3 years ago
Write a Java class to perform the following: 1. Write a method to search the following array using a linear search, ( target ele
Alina [70]

Answer:

Check the explanation

Explanation:

Linear search in JAVA:-

import java.util.Scanner;

class linearsearch

{

  public static void main(String args[])

  {

     int count, number, item, arr[];

     

     Scanner console = new Scanner(System.in);

     System.out.println("Enter numbers:");

     number = console.nextInt();

   

     arr = new int[number];

     System.out.println("Enter " + number + " ");

     

     for (count = 0; count < number; count++)

       arr[count] = console.nextInt();

     System.out.println("Enter search value:");

     item = console.nextInt();

     for (count = 0; count < number; count++)

     {

        if (arr[count] == item)

        {

          System.out.println(item+" present at "+(count+1));

         

          break;

        }

     }

     if (count == number)

       System.out.println(item + " doesn't found in array.");

  }

}

Kindly check the first attached image below for the code output.

Selection Sort in JAVA:-

public class selectionsort {

   public static void selectionsort(int[] array){

       for (int i = 0; i < array.length - 1; i++)

       {

           int ind = i;

           for (int j = i + 1; j < array.length; j++){

               if (array[j] < array[ind]){

                   ind = j;

               }

           }

           int smaller_number = array[ind];  

           array[ind] = array[i];

           array[i] = smaller_number;

       }

   }

     

   public static void main(String a[]){

       int[] arr = {9,94,4,2,43,18,32,12};

       System.out.println("Before Selection Sort");

       for(int i:arr){

           System.out.print(i+" ");

       }

       System.out.println();

         

       selectionsort(arr);

       

       System.out.println("After Selection Sort");

       for(int i:arr){

           System.out.print(i+" ");

       }

   }

}  

Kindly check the second attached image below for the code output.

Bubble Sort in JAVA:-

public class bubblesort {

   static void bubblesort(int[] array) {

       int num = array.length;

       int temp = 0;

        for(int i=0; i < num; i++){

                for(int j=1; j < (num-i); j++){

                         if(array[j-1] > array[j]){

                           

                                temp = array[j-1];

                                array[j-1] = array[j];

                                array[j] = temp;

                        }

                         

                }

        }

   }

   public static void main(String[] args) {

               int arr1[] ={3333,60,25,32,55,620,85};

               

               System.out.println("Before Bubble Sort");

               for(int i=0; i < arr1.length; i++){

                       System.out.print(arr1[i] + " ");

               }

               System.out.println();

                 

               bubblesort(arr1);

               

               System.out.println("After Bubble Sort");

               for(int i=0; i < arr1.length; i++){

                       System.out.print(arr1[i] + " ");

               }

 

       }

}  

Kindly check the third attached image below for the code output.

Binary search in JAVA:-

public class binarysearch {

  public int binarySearch(int[] array, int x) {

     return binarySearch(array, x, 0, array.length - 1);

  }

  private int binarySearch(int[ ] arr, int x,

        int lw, int hg) {

     if (lw > hg) return -1;

     int middle = (lw + hg)/2;

     if (arr[middle] == x) return middle;

     else if (arr[middle] < x)

        return binarySearch(arr, x, middle+1, hg);

     else

        return binarySearch(arr, x, lw, middle-1);

  }

  public static void main(String[] args) {

     binarysearch obj = new binarysearch();

     int[] ar =

       { 22, 18,12,14,36,59,74,98,41,23,

        34,50,45,49,31,53,74,56,57,80,

        61,68,37,12,58,79,904,56,99};

     for (int i = 0; i < ar.length; i++)

        System.out.print(obj.binarySearch(ar,

           ar[i]) + " ");

     System.out.println();

     System.out.print(obj.binarySearch(ar,19) +" ");

     System.out.print(obj.binarySearch(ar,25)+" ");

     System.out.print(obj.binarySearch(ar,82)+" ");

     System.out.print(obj.binarySearch(ar,19)+" ");

     System.out.println();

  }

}

Kindly check the fourth attached image below for the code output

7 0
3 years ago
Which troubleshooting tool enables you to connect to a user's remote computer, view and interact with the user's screen, and cha
DaniilM [7]
That would be Remote assistance.
6 0
3 years ago
"Write an iterative function iterPower(base, exp) that calculates the exponential baseexp by simply using successive multiplicat
sp2606 [1]

Answer:

I am writing the function using Python. Let me know if you want the program in some other programming language.            

def iterPower(base, exp):    

    baseexp = 1

    while exp > 0:

        baseexp = baseexp*base

        exp= exp - 1

    return baseexp

base = 3

exp = 2

print(iterPower(base, exp))

Explanation:

  • The function name is iterPower which takes two parameters base and exp. base variable here is the number which is being multiplied and this number is multiplied exponential times which is specified in exp variable.
  • baseexp is a variable that stores the result and then returns the result of successive multiplication.
  • while loop body keeps executing until the value of exp is greater than 0. So it will keep doing successive multiplication of the base, exp times until value of exp becomes 0.
  • The baseexp keeps storing the multiplication of the base and exp keeps decrements by 1 at each iteration until it becomes 0 which will break the loop and the result of successive multiplication stored in baseexp will be displayed in the output.
  • Here we gave the value of 3 to base and 2 to exp and then print(iterPower(base, exp)) statement calls the iterPower function which calculates the exponential of these given values.
  • Lets see how each iteration works:
  • 1st iteration

baseexp = 1

exp>0 True because exp=2 which is greater than 0

baseexp = baseexp*base

               = 1*3 = 3

So baseexp = 3

exp = exp - 1

      = 2 - 1 = 1    

exp = 1

  • 2nd iteration

baseexp = 3

exp>0 True because exp=1 which is greater than 0

baseexp = baseexp*base

               = 3*3 = 9

So baseexp = 9

exp = exp - 1

      = 1-1 = 0    

exp = 0

  • Here the loop will break now when it reaches third iteration because value of exp is 0 and the loop condition evaluates to false now.
  • return baseexp statement will return the value stored in baseexp which is 9
  • So the output of the above program is 9.
5 0
3 years ago
One vital component of your professional behavior with regard to computing systems today is the creation of​ _________.
zlopas [31]
<span>One vital component of your professional behavior with regard to computing systems today is the creation of​ strong passwords.
It is very important to have a good password on your computer, especially if you are dealing with sensitive data and information. It would be for the best to create such a password which won't be hacked into easily, in case somebody wants to steal your data.
</span>
3 0
3 years ago
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