3x+3y+6z=9
x+3y+2z=5
3x+12y+12z=18
Step 1: use Eq 2 to solve for x
x+3y+2z=5
x= -3y-2z+5
Step 2: Solve for y unsing Eq 1
3x+3y+6z=9
3y= -3x-6z+9
y= -x-2z+3
Step 3: plug in x= -3y-2z+5 to solve for the value of y
y=-x-2z+3
y= (-1)(-3y -2z +5) - 2z+3
y= 3y+2z-5- 2z+3
-2y= -2
y=1
Step 4: plug y= 1 into the x= equation
x= -3y-2z+5
x= -3(1)-2z+5
x= -2z+2
Step 5:Plug y= 1 and x= -2z+2 into the 3rd equation to solve for z
3x+12y+12z=18
12z= -3(-2z+2)-12(1)+ 18
12z= 6z - 6 - 12 +18
6z= -18+18
6z=0
z=0
Step 6: Plug z in to solve for x
x=-2z+2
x= (-2)(0)+2
x= 2
ANSWER:
x,y,z = 2,1,0
answer choice C
Answer:
I think it is C
Step-by-step explanation:
Forgive me if I am wrong the reason I think so is I did one like this last week. Sorry if it is wrong trying to remember.
Answer:
24, 48, 72
Step-by-step explanation:
Common Multiples of 8: 8,16,24,32,40,48,56,64,72,80….
Common Multiples of 12: 12,24,36,48,60,72,………..
Hence the First 3 Least common multiple of 8 and 12= 24, 48, 72
Answer:
Step-by-step explanation:
P1(3,3)
P2(1, -5)
M= (-5-3)/(1-3)=-8/-2=4
Y=4x-9
