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Arlecino [84]
2 years ago
14

A robot can complete 8 tasks in 5/6 hour. Each task takes the same amount of time.

Mathematics
2 answers:
ludmilkaskok [199]2 years ago
7 0

Answer:

A. 6.25

B. Nine tasks

Step-by-step explanation:

soldi70 [24.7K]2 years ago
6 0

Answer:

A.0.10416666625

B. i think it about 6 or 7

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How to solve 1/4 - -4/3 - -1 2/9
Ahat [919]

Answer:

2 29/36

Step-by-step explanation:

So circle the two signs., so the problem is now this:

1/4+4/3+1 2/9

Then you find the GCM, or Greatest Common Denominator.

It is 36. Then, you re-write the new answers

9/36+ 48/36+ 1 18/36

Now we have this:

1 65/36

The answer is 2 29/36

8 0
3 years ago
Evaluate the expression.<br><br> (13^2 - 12^2) ÷ 5​
otez555 [7]
Answer:

5

Step-by-step explanation:

(13^2 - 12^2) ÷ 5

(169 - 144) ÷ 5

25 ÷ 5

5
5 0
2 years ago
HELP ME PLEASE!!!!
horsena [70]
2\sqrt5+3\sqrt5-\sqrt5=(2+3-1)\sqrt5=4\sqrt5\\\\\text{Answer:}\ 4\sqrt5
Look at the square root like "x", then
2\sqrt5+3\sqrt5-\sqrt5=/2x+3x-x=4x/=4\sqrt5

3 0
3 years ago
What is half of 90 ?
Anna35 [415]

half means 2

90 divided by 2

90/2

Answer: 45

3 0
3 years ago
Read 2 more answers
(10 pts) (a) (2 pts) What is the difference between an ordinary differential equation and an initial value problem? (b) (2 pts)
laiz [17]

Answer:

Step-by-step explanation:

(A) The difference between an ordinary differential equation and an initial value problem is that an initial value problem is a differential equation which has condition(s) for optimization, such as a given value of the function at some point in the domain.

(B) The difference between a particular solution and a general solution to an equation is that a particular solution is any specific figure that can satisfy the equation while a general solution is a statement that comprises all particular solutions of the equation.

(C) Example of a second order linear ODE:

M(t)Y"(t) + N(t)Y'(t) + O(t)Y(t) = K(t)

The equation will be homogeneous if K(t)=0 and heterogeneous if K(t)\neq 0

Example of a second order nonlinear ODE:

Y=-3K(Y){2}

(D) Example of a nonlinear fourth order ODE:

K^4(x) - \beta f [x, k(x)] = 0

4 0
3 years ago
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