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vladimir1956 [14]
3 years ago
14

COLOR THEME

Mathematics
1 answer:
elena55 [62]3 years ago
7 0
?!?! whaaatt confused lol
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Please help me
BabaBlast [244]

Answer:

As ΔABC is an <u>isosceles triangle</u>:

⇒ BA = BC  
(the dashes on the line segments indicate they are of equal measure)

⇒ ∠BAC = ∠BCA = 55°

⇒ ∠BCA = ∠BAD = 55°

Angles on a <u>straight line</u> sum to 180°

⇒ ∠ADE + ∠EDC = 180°

⇒ 98° + ∠EDC = 180°

⇒ ∠EDC = 82°

As BE intersects AC, the <u>vertically opposite angles</u> are <em>equal</em>:

⇒ ∠BDC = ∠ADE = 98°

⇒ ∠ADB = ∠EDC = 82°

Interior angles in a triangle sum to 180°

⇒ ∠BAD + ∠ADB + ∠ABD = 180°

⇒ 55° + 82° + ∠ABD= 180°

⇒ ∠ABD = 180° - 55° - 82°

⇒ ∠ABD = 43°

5 0
2 years ago
Read 2 more answers
Write an equation in standard form that is parallel to the line y = 2x - 1 that passes through the point (1, 2). 2x - y = 0 O x
timofeeve [1]

Answer:

2x - y = 0

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 2x - 1 ← is in slope- intercept form

with slope m = 2

Parallel lines have equal slopes, thus

y = 2x + c ← is the partial equation

To find c substitute (1, 2) into the partial equation

2 = 2 + c ⇒ c = 2 - 2 = 0

y = 2x ← equation in slope- intercept form

Subtract y from both sides

0 = 2x - y , that is

2x - y = 0 ← equation in standard form

5 0
3 years ago
She has enough bricks to cover 60 square feet. She wants the length of the patio to be 4 feet longer than the width. What dimens
Natalija [7]

Answer:

10 feet length and 6 feet width.

Step-by-step explanation:

If the total area of the patio is going to be equal to 60 square feet and the length is going to be 4 feet longer than the width, the dimensions that she should use for the patio are 10 feet for the length and 6 feet for the width which will equal to 60 square feet in total.

I hope this answer helps.

3 0
3 years ago
Create an explicit formula for the following sequence 1/3,-1,3,-9
Travka [436]

Answer:

multiply by -3

Step-by-step explanation:

1/3 gives -3/3=-1

-1*-3=3

3*-3=-9

it defines the function f so that f(x)=-3x

8 0
3 years ago
Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview
svetlana [45]

Answer:  The required solution is

y=(-2+t)e^{-5t}.

Step-by-step explanation:   We are given to solve the following differential equation :

y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)

Let us consider that

y=e^{mt} be an auxiliary solution of equation (i).

Then, we have

y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.

Substituting these values in equation (i), we get

m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.

So, the general solution of the given equation is

y(t)=(A+Bt)e^{-5t}.

Differentiating with respect to t, we get

y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.

According to the given conditions, we have

y(0)=-2\\\\\Rightarrow A=-2

and

y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.

Thus, the required solution is

y(t)=(-2+1\times t)e^{-5t}\\\\\Rightarrow y(t)=(-2+t)e^{-5t}.

6 0
3 years ago
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