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vladimir1956 [14]
2 years ago
14

COLOR THEME

Mathematics
1 answer:
elena55 [62]2 years ago
7 0
?!?! whaaatt confused lol
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Shown here is a frequency distribution for the rise in tides at 30 selected locations in the U.S.Find the variance and standard
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It’s is going to be 15 since 30/2 equals 15
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1. To encourage public transportation, Avery wants to give some friends envelopes with bus tickets and subway tickets in them. I
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5 .This is called the greatest common factor.

You can list all the factors(ways to divide) of each number and find the biggest one.

15'1,3,5,15

10'1,2,5,10

The greatest they share is 5


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Jim rented a truck for one day . There was a base fee of $18.95 and there was an additional charge of 74 cents for each mile dri
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Answer:

136 miles

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subtract $119.59 with how much he rented the truck for, which is $18.95 which makes his money at $100.64, then divide by how much each mile costed which was 74 cents

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ILL GIVE BRAINLEST
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Answer:

A. 7

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3 years ago
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How many possible committees of 4 people can be chosen from 15 men and 20 women so that at least two women should be on each com
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<span>If there has to be 2 men and 2 women, we know that we must take a group of 2 men out of the group of 15 men and a group of 2 women out of the group of 20 women. Therefore, we have:

(15 choose 2) x (20 choose 2)


(15 choose 2) = 105

(20 choose 2) = 190

190*105 = 19950

Therefore, there are 19950 ways to have a group of 4 with 2 men and 2women.</span>

 

<span>If there has to be 1 man and 3 women, we know that we must take a group of 1 man out of the group of 15 men and a group of 3 women out of the group of 20 women. Therefore, we have:

(15 choose 1) x (20 choose 3)


(15 choose 1) = 15

(20 choose 3) = 1140

15*1140 = 17100

Therefore, there are 17100 ways to have a group of 4 with 3 women and 1 man.</span>

 

<span>We now find the total outcomes of having a group with 4 women.

We know this is the same as saying (20 choose 4) = 4845</span>

Therefore, there are 4845 ways to have a group of 4 with 4 women.

 

We now add the outcomes of 2 women, 3 women, and 4 women and get the total ways that a committee can have at least 2 women.

 

19950 + 17100 + 4845 = 41895 ways that there will be at least 2 women in the committee


5 0
3 years ago
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