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bogdanovich [222]
3 years ago
8

What is 23+ 23+76+87+90

Mathematics
2 answers:
Karolina [17]3 years ago
8 0

Answer:

the answer is 299. Brainliest ????please???

SCORPION-xisa [38]3 years ago
5 0
23+23+76+87+90 = 299

Hope this helps.
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Mr. Jones bought a cloth of length 3890 cm. How much is the length in m and cm?
devlian [24]

Answer:

38m and 90cm

1m = 100cm

3890cm = 38m and 90cm

Step-by-step explanation:

1m = 100cm

3890cm = 38m and 90cm

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3 years ago
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I honestly don’t understand this at all can you help?
blondinia [14]
A. the first box is 7 
    the second box is 2
    the third box is 100 
    the fourth box is 6.5
    RULE: times 3 + 2
b. the first box is 45/2
    the second box is -0.75
    the third box is 0
    the fourth box is 2.75 
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c. the first box is 1 1/2
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    the fourth box is -1.75
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3 years ago
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Geometry 10th Grade. Help but only with right answers don't waste the answers
skelet666 [1.2K]

Answer:

the last one, d

Step-by-step explanation:

simplify it and you get x+3, y+1 which is the translation on the graph.

8 0
2 years ago
where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤
marusya05 [52]

THIS IS THE COMPLETE QUESTION BELOW

The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.

Answer

$168.27

Step by step Explanation

Given p=90000/400+3x

With the limits of 40 to 50

Then we need the integral in the form below to find the average price

1/(g-d)∫ⁿₐf(x)dx

Where n= 40 and a= 50, then if we substitute p and the limits then we integrate

1/(50-40)∫⁵⁰₄₀(90000/400+3x)

1/10∫⁵⁰₄₀(90000/400+3x)

If we perform some factorization we have

90000/(10)(3)∫3dx/(400+3x)

3000[ln400+3x]₄₀⁵⁰

Then let substitute the upper and lower limits we have

3000[ln400+3(50)]-ln[400+3(40]

30000[ln550-ln520]

3000[6.3099×6.254]

3000[0.056]

=168.27

the average price p on the interval 40 ≤ x ≤ 50 is

=$168.27

8 0
3 years ago
Graph f (.x) = x3 – 4x3 + x2 + 2. Identify the x-intercepts and the points where the local maximums and local
liubo4ka [24]

Answer:

um oof

Step-by-step explanation:

4 0
3 years ago
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