What is 23+ 23+76+87+90

Mathematics

2 answers:

Karolina [17]3 years ago

8 0

Answer:

the answer is 299. Brainliest ????please???

SCORPION-xisa [38]3 years ago

5 0

23+23+76+87+90 = 299

Hope this helps.

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Saritha will construct a rectangle that has a height of 4 units and an area of up to 48 square units. What inequality represents

Leto [7]

Answer:

Remember that for a square of height H and length L, the area will be:

A = H*L

In this case, we know that the height is H = 4 units.

And the area is up to 48 square units

This means that the maximum possible area of this rectangle is 48 square units.

Then we have:

A ≤ 48 square units.

And we also could add:

0 square units < A ≤ 48 square units.

Now we can replace A by H*L = L*(4units)

0 square units < L*(4 units) ≤ 48 square units.

Now we need to divide all 3 sides by 4 units.

(0 square units)/(4 units) < L ≤ (48 square units)/(4 units)

0 units < L ≤ 12 units.

This is the range of lengths that Saritha can use to reconstruct the rectangle.

Now if we define b as the length of the bases, then we will use:

b = height = 4units.

Then:

1b = 4units.

(1 b/4units) = 1

This means that:

12 units = (12 units)*1 = (12 units)*(1 b/4units) = (12/4) b = 3 b

Then the range of possible values of L is:

0b < L ≤ 3b

8 0

3 years ago

8.23 A manufacturing company produces electric insulators. You define the variable of interest as the strength of the insulators

Kitty [74]

Answer:

The 95% confidence interval estimate for the population mean force is (1691, 1755).

Step-by-step explanation:

According to the Central Limit Theorem if we have an unknown population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally.

The sample selected here is <em>n</em> = 30.

Thus, the sampling distribution of the sample mean will be normal.

Compute the sample mean and standard deviation as follows:

$\bar x=\frac{1}{n}\sum x=\frac{1}{30}\times 51702=1723.4\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{30-1}\times 232561.2}=89.55$