So focusing on x^4 + 5x^2 - 36, we will be completing the square. Firstly, what two terms have a product of -36x^4 and a sum of 5x^2? That would be 9x^2 and -4x^2. Replace 5x^2 with 9x^2 - 4x^2: 
Next, factor x^4 + 9x^2 and -4x^2 - 36 separately. Make sure that they have the same quantity inside of the parentheses: 
Now you can rewrite this as 
, however this is not completely factored. With (x^2 - 4), we are using the difference of squares, which is 
. Applying that here, we have 
. x^4 + 5x^2 - 36 is completely factored.
Next, focusing now on 2x^2 + 9x - 5, we will also be completing the square. What two terms have a product of -10x^2 and a sum of 9x? That would be 10x and -x. Replace 9x with 10x - x: 
Next, factor 2x^2 + 10x and -x - 5 separately. Make sure that they have the same quantity on the inside: 
Now you can rewrite the equation as 
. 2x^2 + 9x - 5 is completely factored.
<h3><u>Putting it all together, your factored expression is
</u></h3>
Answer: 2 19/24 hours was spent in practising.
Step-by-step explanation:
During the first hour, they practiced for 5/8 of an hour. During the second hour, they practiced for 2/3 of an hour. This means that the total time for which they practiced in the first 2 hours would be
5/8 + 2/3 = 31/24 hours
During the last two hours, they first practiced for 3/5 of an hour, took a 1/2 hour break and then practiced the rest of the time. This means that the rest of the time for which they practiced is
2 - (3/5 + 1/2) = 2 - 11/10 = 9/10
Therefore, the time they spent practicing in total would be
31/24 + 3/5 + 9/10 = 67/24 =
2 19/24 hours
It is SAS because
1) it is given that sides are equal (AB=CD)
2)it is also given that angles B and C are equal
3) BC is a common side so it is equal in both triangles.
answer: SAS
Answer:
Third option: x=0 and x=16
Step-by-step explanation:
Isolating √(2x+4): Addind √x both sides of the equation:
Squaring both sides of the equation:
Simplifying on the left side, and applying on the right side the formula:
Isolating the term with √x on the right side of the equation: Subtracting 4 and x from both sides of the equation:
Squaring both sides of the equation:
This is a quadratic equation. Equaling to zero: Subtract 16x from both sides of the equation:
Factoring: Common factor x:
x (x-16)=0
Two solutions:
1) x=0
2) x-16=0
Solving for x: Adding 16 both sides of the equation:
x-16+16=0+16
x=16
Let's prove the solutions in the orignal equation:
1) x=0:
x=0 is a solution
2) x=16
x=16 is a solution
Then the solutions are x=0 and x=16
