Justin's statement would be the best. In order to change 3/5 into 6/10, both sides would need to be multiplied by 2.
Answer:
a) (0.5256,0.5944)
c) Criticism is invalid
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 560
Proportion of mislabeled = 56%

a) 90% Confidence interval:


Putting the values, we get:

b) Interpretation of confidence interval:
We are 90% confident that the true proportion of all seafood in the country that is mislabeled or misidentified is between 0.5256 and 0.5944 that is 52.56% and 59.44%.
c) Validity of criticism
Conditions for validity:

Verification:

Both the conditions are satisfied. This, the criticism is invalid.
More than one liter because it only depends how bog your sink is...I believe it is more than one liter
Answer:
Step-by-step explanation:
x = 55
x + 55 = 110
x + 20 = 75
x + 65 = 120