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Ierofanga [76]
3 years ago
8

Simplify. Rewrite the expression in the form b^n. b^10/b^6

Mathematics
2 answers:
Vlad1618 [11]3 years ago
6 0

Answer:

<h2>The answer is b⁴</h2>

Step-by-step explanation:

\frac{ {b}^{10} }{ {b}^{6} }

Using the rules of indices

That's

\frac{ {a}^{x} }{ {a}^{y} }  =  {a}^{x - y}

Since the bases are the same and are dividing we subtract the exponents

So we have

\frac{ {b}^{10} }{ {b}^{6} }  =  {b}^{10 - 6}

We have the final answer as

<h2>b⁴</h2>

Hope this helps you

MaRussiya [10]3 years ago
4 0

Answer:

b⁴

Step-by-step explanation:

b¹⁰ / b⁶ = b¹⁰ ⁻⁶ = b⁴

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Answer:

a) 0.98% probability that 17 of the 29 people are men.

b) 3.86% probability that the first woman is reached on the 8th call

Step-by-step explanation:

For each person chosen by the agency, there are only two possible outcomes. Either it is a man, or it is a woman. The probability of selecting a man or a women in each trial is independent from other trials. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

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(a) What is the probability that 17 of the 29 people are men?

This is P(X = 17) when n = 29, p = 0.78. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 17) = C_{29,17}.(0.78)^{17}.(0.22)^{12} = 0.0098

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On the first 7 trials, all men, each with a 78% probability.

On the 8th trial, a women, with a 22% probability. So

P = (0.78)^{7}*0.22 = 0.0386

3.86% probability that the first woman is reached on the 8th call

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3 years ago
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