Answer:
x = 2 1/3
y = 14 / (2 1/3) = 14 / (7/3) = 14*3/7 = 42/7 = 6
y = 6
x = 4 1/5
y = 14 / (4 1/5) = 14 / (21/5) = 14*5/21 = 70/21 = 3 7/21 = 3 1/3
y = 3 1/3
x = 7/6
y = 14 / (7/6) = 14*6 / 7 = 12
y = 12
Step-by-step explanation:
Answer:
10:30 A.M
Step-by-step explanation:
Answer:
Step-by-step explanation:
We first need to define a couple of variables. Let s = the cost of 1 squash and z = the cost of 1 zucchini.
Now lets translate the words into algebra:
"The cost of 5 squash and 2 zucchini is $1.32" ===> 5s + 2z = 1.32
"Three squash and 1 zucchini cost $0.75" ===> 3s + z = 0.75
There are several ways to solve systems of equations. Let's use substitution. We can find what z equals in terms of s by manipulating the second equation:
3s + z = 0.75
-3s -3s
------------ -------------
z = -3s +0.75
Now lets substitute (-3s + 0.75) into the first equation for z, then solve for s:
5s + 2(-3s + 0.75) = 1.32
Can you handle it from here?
(Hint: Once you have solved for s, you can substitute that value back into either of the equations and solve for z.)
. Then by the distributive property,
