I believe it is the ratio 3 : 1.
<u>18 students chose the turkey sandwich</u>.
Since the class has a total of 24 students, we can deduce that <u>6 students chose the vegetarian sandwich</u>.
This gives us a ratio of 18 : 6.
When simplified, we get a ratio of 3 : 1.
The cost of a senior citizen ticket is $15 and the cost of a student ticket is $12.
How did I get this?
We know that 6 citizen tickets and 7 student stickers sold for $174 the first day. And 10 citizen tickets and 14 student tickets sold for $318 the second day.
1. create two equations out of this: C= citizen cost per ticket and S = student cost per ticket.
6C + 7S = $174
10C + 14S = $318
2. Use process of elimination. Multiply the first equation by 2 because we want two variables to cancel out.
-12C - 14S = -$348
10C + 14S = $318
Combine like terms.
-2C = $30
Divide by -2 on both sides. The left side cancels out.
C = $30/-2
C = -$15 (In this case the negative doesn't matter)
C = $15 (cost of senior citizen ticket)
Plug the value of C into any of the two equations so we can get the value of S.
6($15) + 7S = $174
Distribute the 6 into the parenthesis.
$90 + 7S = $174
Subtract both sides by $90 and the left side will cancel out.
7S = $84
Divide both sides by 7.
S = $12
Student ticket: $12
Senior citizen ticket: $15
Answer:
well, x = 5
Step-by-step explanation:
here,
EB Is parallel to DC , so
Angle AEB = Angle ADE
( because they are corresponding angle pair )
Angle ABE = Angle ACD
( because they are corresponding angle pair )
triangle ADC Is similar to triangle AEB
(By AA similarity criteria )
hence AE / ED = AB / BC ( by CPCT )
so 24/10 = 12/x
=》 24/12= 10/x
=》 x = 5
okay i hope u got it
Answer:
907.46 mm2
Step-by-step explanation:
Area of circle = (¶d^2)/4
d = 34 mm
Therefore
Area A = (3.14 x 34^2)/4
= 907.46 mm2
There are 10 balls in the Urn Total.
Red: 6
Green: 4
Question One: The probability that five red and two green is selected is likely. (as that is over half for both)
Question Two: Impossible. There is only 6 red balls, and 7 are taken from the urn. Thus it would at most be possible for 6 red and 1 green.
Question Three: At least four is likely, as there is more red then green in the Urn.
Hope I helped!
(Mark Brainliest if you can please!)
