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Ksenya-84 [330]
3 years ago
6

Solve using the standard algorithm 1.03 +0.08

Mathematics
1 answer:
nataly862011 [7]3 years ago
4 0

Answer:

1.11

Step-by-step explanation:

1.03+0.08=1.11

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Assume that random guesses are made for eight multiple choice questions on an SAT test, so that there are n= 8 trials, each with
alina1380 [7]

Answer:

0.80589

Step-by-step explanation:

So all of the numbers of correct answers less than 4 are 0,1,2,3

We need to calculate the probability for each separately and then add them together.

To find the probability we have to first find the combination. We know that there’s n=8 trials and that p=0.3. So 1-0.3 gives us 0.7.

The combination formula is: ! / (!(−)!)

So the n would always =8, and the r would be 0,1,2,3. So you would have to calculate it for 0,1,2,3 Separately. This can be done by hand or you can use a simple combinations calculator online.

For 0;

The combination is 1,

1 x 0.3^0 x 0.7^8-0 =

0.057648

For 1;

The combination is 8,

8 x 0.3^1 x 0.7^8-1 =

0.19765

For 2;

The combination is 28

28 x 0.3^2 x 0.7^8-2 =

0.296475

For 3;

The combination is 56

56 x 0.3^3 x 0.7^8-3 =

0.254122

All that’s left is to add these four numbers;

0.057647 + 0.19765 + 0.296475 + 0.254122 = 0.80589

4 0
3 years ago
10% of 65 pls help and explain the steps to get total answer​
sergij07 [2.7K]
10% of 65
Of means multiply
=0.1 x 65
=6.5

Or you can use another way which is (part/whole) *(percent/100)

Whole=65
Percent=10
And part(part of 65)=unknown

(X/65)* (10/100)
Cross multiply
x= 6.5

So 10% of 65 is 6.5
5 0
2 years ago
20000×50×45×0×23×5×6+229+466+7+5+8+9+1+2+3+45+6+7+8+9+10. Hope you like question don't answer if you don't want to. Have a great
Lemur [1.5K]
815? but have a great day as well!
4 0
3 years ago
For a binomial distribution with p = 0.20 and n = 100, what is the probability of obtaining a score less than or equal to x = 12
notsponge [240]
The binomial distribution is given by, 
P(X=x) =  (^{n}C_{x})p^{x} q^{n-x}
q = probability of failure = 1-0.2 = 0.8
n = 100
They have asked to find the probability <span>of obtaining a score less than or equal to 12.
</span>∴ P(X≤12) = (^{100}C_{x})(0.2)^{x} (0.8)^{100-x}
                    where, x = 0,1,2,3,4,5,6,7,8,9,10,11,12                  
∴ P(X≤12) = (^{100}C_{0})(0.2)^{0} (0.8)^{100-0} + (^{100}C_{1})(0.2)^{1} (0.8)^{100-1} + (^{100}C_{2})(0.2)^{2} (0.8)^{100-2} + (^{100}C_{3})(0.2)^{3} (0.8)^{100-3} + (^{100}C_{4})(0.2)^{4} (0.8)^{100-4} + (^{100}C_{5})(0.2)^{5} (0.8)^{100-5} + (^{100}C_{6})(0.2)^{6} (0.8)^{100-6} + (^{100}C_{7})(0.2)^{7} (0.8)^{100-7} + (^{100}C_{8})(0.2)^{8} (0.8)^{100-8} + (^{100}C_{9})(0.2)^{9} (0.8)^{100-9} + (^{100}C_{10})(0.2)^{10} (0.8)^{100-10} + (^{100}C_{11})(0.2)^{11} (0.8)^{100-11} + (^{100}C_{12})(0.2)^{12} (0.8)^{100-12}


Evaluating each term and adding them you will get,
P(X≤12) = 0.02532833572
This is the required probability. 
7 0
3 years ago
If Q is between P and R, then PQ+QR=PR what is the propety
Marina86 [1]

Answer:

Segment Addition Postulate

Step-by-step explanation:

8 0
3 years ago
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