Can someone help me?

Mathematics

2 answers:

Marina86 [1]2 years ago

8 0

M = -3, hope it was helpful! :)

Pani-rosa [81]2 years ago

5 0

Answer: m=−3

Step-by-step explanation: −40−2(3m+1/2)=7m−2

−40+(−2)(3m)+(−2)(1/2)=7m+−2

−40+−6m+−1=7m+−2

(−6m)+(−40+−1)=7m−2

−6m+−41=7m−2

−6m−41−7m=7m−2−7m

−13m−41+41=−2+41

−13m/−13=39/−13

m=−3

What mistake I guess Keith did make is he subtracted 2 from -39 which equaled to -37 which caused him divide -37 by 13 when it should have been 39 divided by 13 because he should have left 39 alone and not have subtracted 2 from it also it should not have been negative basically what I'm trying to say is that he did his division and subtraction wrong.

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5) Two machines M1, M2 are used to manufacture resistors with a design

Basile [38]

Answer:

Since M1 has the higher probability of being in the desired range, we choose M1.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Two machines M1, M2 are used to manufacture resistors with a design specification of 1000 ohm with 10% tolerance.

So we need the machines to be within 1000 - 0.1*1000 = 900 ohms and 1000 + 0.1*1000 = 1100 ohms.

For each machine, we need to find the probabilty of the machine being in this range. We choose the one with the higher probability.

M1:

Resistors of M1 are found to follow normal distribution with mean 1050 ohm and standard deviation of 100 ohm. This means that $\mu = 1050, \sigma = 100$