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jekas [21]
2 years ago
15

If 2x - 5y – 7 = 0 is perpendicular to the line ax - y - 3 = 0 what is the value of a ?

Mathematics
1 answer:
faltersainse [42]2 years ago
6 0

Answer:

D) a = - 5/2

Step-by-step explanation:

2x -5y - 7 = 0

5y = 2x - 7

y = 2/5 x - 7

the slope of this line is therefore 2/5 (factor of x).

the perpendicular slope is then (exchange y and x and flip the sign) -5/2, which is then a and the factor of x.

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Please help ASAP 25 pts + brainliest to right/best answer
zhuklara [117]

Answer:


Step-by-step explanation:

LOGb(x)=y

4^5=1024

= log(4)1024=5

4 0
3 years ago
Name the kind or kinds of symmetry the following figure has: A
denpristay [2]
It is a straight line of symmetry because if you have a paper A and you fold it, it will form a straight line, and that is also meaning a straight line of symmetry. If you fold it any other way, it will not be a line of symmetry.

Hope this helps you ;)
6 0
3 years ago
Choose the model that represents the function
kirill [66]

Answer:

OPTION D

Step-by-step explanation:

We have to determine which option determines the function given above.

To determine the function, just substitute the values and compare LHS and RHS.

we have $ f(4) = 18 $

$ f(-2) = -12 $

$ f(0) = -2 $

$ f(-3) = -17 $

Here, $ x $ is the domain and $ f(x) $ is the co-doamin.

Therefore, $ x = \{4, -2, 0, -3\} $

Now, OPTION A: $ f(x) =  2x - 5 $

Substitute x = 4. We get f(x) = 3 $ \ne $ 18.

So, OPTION A is rejected.

Similarly, OPTION B: $ f(x) = 5x + 2 $

Substitute x = 4. We get f(4) = 22 $ \ne $18.

It is rejected as well.

Now, for OPTION C: $ f(x) = \frac{x}{2} - 5 $

Substitute x = 4. We get f(4) = -3 $ \ne $ 18.

So, OPTION C is also rejected.

OPTION D: $ f(x) =  5x - 2 $

Substitute x = 4. We get f(4) = 18.

Substitute the remaining points in domain as well. We notice that it exactly matches the given function. So, OPTION D is the answer.

8 0
3 years ago
Hii happy holidays !! any help is appreciated consider the following graph
Rom4ik [11]

9514 1404 393

Answer:

  A, M, N, F

Step-by-step explanation:

I find it easier to look at the graph, rather than mess with the coordinate transformations. Each image point is the same distance from the line of reflection that its pre-image point is. The line joining the two points is perpendicular to the line of reflection.

See attached for the reflected points.

__

The red and turquoise dashed lines are the lines y=x and y=-x, respectively. The same-colored arrows show the reflection of the relevant point.

_____

The transformations of interest are ...

  (x, y) ⇒ (y, x) . . . . reflection over y = x

  (x, y) ⇒ (-x, y) . . . . reflection over y-axis

  (x, y) ⇒ (x, -y) . . . . reflection over x-axis

  (x, y) ⇒ (-y, -x) . . . . reflection over y = -x

8 0
3 years ago
Solve the system of equations {3x-y=10, -x y=12} for Y
Novosadov [1.4K]
3x - y = 10 . . . (1)
-x + y = 12 . . . (2)

(1) + (2) => 2x = 22 => x = 22/2 = 11

From 2, -11 + y = 12 => y = 12 + 11 = 23
5 0
3 years ago
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