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Margaret [11]
3 years ago
9

What is the Area of this composite polygon

Mathematics
1 answer:
melomori [17]3 years ago
6 0

Answer:

136

Step-by-step explanation:

I LOVE DOING THESE

16x7=112

8x6=48

48x0.5=24

112+24=136

You might be interested in
If the range of the function g(x) =3x+2 is {2,5,11,17}, find the domain. ​
Aleonysh [2.5K]

Answer:

(0,1,3,5)

Step-by-step explanation:

Set g(x) equal to each respective range and solve for x

3x + 2 = 2

3x + 2 = 5

3x + 2 = 11

3x + 2 = 17

If we solve for each, we get

x = 0

x = 1

x = 3

x = 5

So our domain is

(0,1,3,5)

6 0
3 years ago
Which triangle defined by three points on the coordinate plane is congruent with the triangle illustrated? Explain.
yaroslaw [1]

Answer:c

Step-by-step explanation:

You divide by the dividend and multiple my ding dong in your face

3 0
4 years ago
Some scientists believe alcoholism is linked to social isolation. One measure of social isolation is marital status. A study of
frez [133]

Answer:

1) H0: There is independence between the marital status and the diagnostic of alcoholic

H1: There is association between the marital status and the diagnostic of alcoholic

2) The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

3) \chi^2 = \frac{(21-33.143)^2}{33.143}+\frac{(37-41.429)^2}{41.429}+\frac{(58-41.429)^2}{41.429}+\frac{(59-46.857)^2}{46.857}+\frac{(63-58.571)^2}{58.571}+\frac{(42-58.571)^2}{58.571} =19.72

4) df=(rows-1)(cols-1)=(3-1)(2-1)=2

And we can calculate the p value given by:

p_v = P(\chi^2_{2} >19.72)=5.22x10^{-5}

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.72,2,TRUE)"

Since the p value is lower than the significance level so then we can reject the null hypothesis at 5% of significance, and we can conclude that we have association between the two variables analyzed.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

                    Diag. Alcoholic   Undiagnosed Alcoholic    Not alcoholic    Total

Married                     21                              37                            58                116

Not Married              59                             63                            42                164

Total                          80                             100                          100              280

Part 1

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is independence between the marital status and the diagnostic of alcoholic

H1: There is association between the marital status and the diagnostic of alcoholic

The level os significance assumed for this case is \alpha=0.05

Part 2

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

Part 3

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{total col * total row}{grand total}

And the calculations are given by:

E_{1} =\frac{80*116}{280}=33.143

E_{2} =\frac{100*116}{280}=41.429

E_{3} =\frac{100*116}{280}=41.429

E_{4} =\frac{80*164}{280}=46.857

E_{5} =\frac{100*164}{280}=58.571

E_{6} =\frac{100*164}{280}=58.571

And the expected values are given by:

                    Diag. Alcoholic   Undiagnosed Alcoholic    Not alcoholic    Total

Married             33.143                       41.429                        41.429                116

Not Married     46.857                      58.571                        58.571                164

Total                   80                              100                             100                 280

And now we can calculate the statistic:

\chi^2 = \frac{(21-33.143)^2}{33.143}+\frac{(37-41.429)^2}{41.429}+\frac{(58-41.429)^2}{41.429}+\frac{(59-46.857)^2}{46.857}+\frac{(63-58.571)^2}{58.571}+\frac{(42-58.571)^2}{58.571} =19.72

Part 4

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(3-1)(2-1)=2

And we can calculate the p value given by:

p_v = P(\chi^2_{2} >19.72)=5.22x10^{-5}

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.72,2,TRUE)"

Since the p value is lower than the significance level so then we can reject the null hypothesis at 5% of significance, and we can conclude that we have association between the two variables analyzed.

7 0
4 years ago
Sprinter #1 is running at a speed of 96 inches/second. Sprinter #2 is running at a speed of 475
ladessa [460]

Answer:

Sprinter #1

Step-by-step explanation:

Sprinter #1 is running at 96/12 feet per second: 8 feet per second

Sprinter  #2 is running at 475/60 feet per second: approximately 7.9 feet per second

Sprinter #1 covers more distance per second.

6 0
2 years ago
68.397384 rounded to the nearest hundredth
Evgen [1.6K]

Answer:

the answer is 68.397

Step-by-step explanation:

becasue you round 3 down on the 4 digit after the decimal

4 0
3 years ago
Read 2 more answers
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