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Alexus [3.1K]
2 years ago
5

What Are The Areas Of The Squares Off Of The Legs❓

Mathematics
1 answer:
fgiga [73]2 years ago
4 0
The legs of the traingle are the sides that touch the right angle
the lolngest side is the hypotnuse

use the pythagorean theorem that say
if a and b are legs and c=hypotonuse
a^2+b^2=c^2

the picture illustrates this concept

so we have the legs are 6 and 8
the areas are 6^2 and 8^2 which is 36 and 64

areas are 36 squaer units and 64 square units
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The answer is 290=50+20x
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What is the measure of angle 2​
ad-work [718]

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45

Step-by-step explanation:

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The measure of angle 2 is 45.

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Universal Pet house sells vinyl doghouse and treated lumber doghouses. It takes the company 5 hours to build a vinyl doghouses a
LuckyWell [14K]

Answer:

The system of equations is :

Equation 1- 5x+2y=50

Equation 2- x+2y=30

Number of vinyl doghouse = 5

Number of treated lumber doghouse =12.5

Step-by-step explanation:

Let x be the number of vinyl doghouses

y be the number of treated lumber doghouses

→If it takes the company 5 hours to build a vinyl doghouses and 2 hours to build a treated lumber doghouse. The company dedicates 50 hours every week towards assembling and painting doghouses.

Equation 1- 5x+2y=50

→It takes an additional hour to paint each vinyl doghouse and an additional 2 hours to assemble each treated lumber doghouse. The company dedicates 30 hours every week towards assembling and paining dog houses.

Equation 2- x+2y=30

→When we solve these equation we get the number of  vinyl doghouse and treated lumber doghouse.

Subtract equation 2 from equation 1

5x+2y-x-2y=50-30

4x=20

x=\frac{20}{4}

x=5

Put value of x in equation 2

x+2y=30

5+2y=30

2y=25

y=\frac{25}{2}

y=12.5

Therefore, number of vinyl doghouse = 5, number of treated lumber doghouse =12.5

4 0
2 years ago
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Please answer to receive ten points. I'll vote who answers first the brainliest if its correct. 
beks73 [17]

The distance between points P_1(x_1,y_1) and P_2(x_2,y_2) can be calculated using formula

P_1P_2=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}.

1.

AB=\sqrt{(-7-(-11))^2+(8-4)^2}=\sqrt{16+16}=\sqrt{32}=4\sqrt{2}\approx 5.657.

2.

AC=\sqrt{(-4-(-11))^2+(4-4)^2}=\sqrt{49+0}=\sqrt{49}=7.

3.

CB=\sqrt{(-7-(-4))^2+(8-4)^2}=\sqrt{9+16}=\sqrt{25}=5.

Then

P_{ABC}=5.657+7+5=17.657\approx 17.7

Answer: correct choice is C.

3 0
2 years ago
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