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2 years ago

9

How does a slope relate to the unit rate

1 answer:

Genrish500 [490]2 years ago

8 0

Because of speed, acceleration and movement.

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5,3,-7,-8,-2 order from greatest to least

Burka [1]

Answer

-8, -7, -2, 3, 5

Explanation

Positive numbers go up as they increase.

Negative numbers go up as they decrease.

3 0

2 years ago

Use lagrange multiplier techniques to find the local extreme values of f(x, y) = x2 − y2 − 2 subject to the constraint x2 + y2 =

dexar [7]

Given $f(x,\ y)=x^2-y^2-2$ subject to the constraint $x^2+y^2=16$

Let $g(x,\ y)=x^2+y^2$ .

The gradient vectors of $f$ and $g$ are:

$\nabla f(x,\ y)=\langle2x,-2y\rangle$ and $\nabla g(x,\ y)=\langle2x,2y\rangle$

By Lagrange's theorem, there is a number $\lambda$ , such that

$\langle2x,-2y\rangle=\lambda\langle2x,2y\rangle=\langle2\lambda x,2\lambda y\rangle$

$\lambda=\pm1$

It can be seen that $f(x,\ y)=x^2-y^2-2$ has local extreme values at the given region.

6 0

3 years ago

You have 100 feet of fencing and decide to make a rectangular garden. What is the largest area enclosed

k0ka [10]

Answer:

625 ft^2

Step-by-step explanation:

Given

$P = 100$ --- perimeter

Required

The largest area

The perimeter is calculated as:

$P = 2 * ( L + W)$

So, we have:

$2 * ( L + W) = 100$

Divide both sides by 2

$L + W = 50$

Make L the subject

$L = 50 - W$

The area is calculated as:

$A= L * W$

Substitute $L = 50 - W$

$A= (50 - W) * W$

Open bracket

$A = 50W - W^2$

Differentiate with respect to W

$A' = 50 -2W$

Set to 0; to get the maximum value of W

$50 - 2W = 0$

Collect like terms

$-2W = -50$

Divide by -2

$W = 25$

So, the maximum area is:

$A = 50W - W^2$

$A = 50 * 25 - 25^2$

$A = 1250 - 625$

$A = 625$

3 0

2 years ago

A 3mL unit dose of levalbuterol HCl contains 0.63mg of active ingredient. If 2 unit doses are used, how many mg of active ingred

Sergio039 [100]

Answer: 0.42 mg

Step-by-step explanation:

Given : A 3mL unit dose of levalbuterol HCl contains 0.63mg of active ingredient.

Then , the amount of active ingredient in 1 ml dose of levalbuterol HCl = $\dfrac{0.63}{3}$

$=\dfrac{63}{300}=\dfrac{21}{100}=0.21\ mg$

Hence, the amount of active ingredient in 2 ml dose of levalbuterol HCl will be :-

$2\times0.21=0.42\ mg$

Hence, the amount of active ingredient in 2 ml dose of levalbuterol HCl =0.42 mg

6 0

3 years ago

Given the following diagram, what is the value for x?<br> A) 1<br> B) 9<br> C) 18√2<br> D) 18√3

never [62]

Answer:

x=9

Step-by-step explanation:

8 0

2 years ago