Answer:
x=0
Step-by-step explanation:
If you combine like terms it is x^2 +6x -27=-27
x^2 +6x =0
x^2=0
x=0
complette the square to get vertex form or y=a(x-h)^2+k
(h,k) is vertex
1. group x terms, so for y=ax^2+bx+c, do y=(ax^2+bx)+c
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2, factor out the leading coefinet (constant in front of the x^2 term), basicallly factor out a
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3. take 1/2 of the linear coefient (number in
front of the x), and square it ,then add negative and positive of it
inside parnthases
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4. complete the squre and expand
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so
y=-1/4x^2+4x-19
group
y=(-1/4x^2+4x)-19
undistribute -1/4
y=-1/4(x^2-16x)-19
take 1/2 of -16 and squer it to get 64 then add neg and pos inside
y=-1/4(x^2-16x+64-64)-19
factorperfect square
y=-1/4((x-8)^2-64)-19
expand
y=-1/4(x-8)^2+16-19
y=-1/4(x-8)^2-3
vertex is (8,-3)
Answer:
36 
Step-by-step explanation:
<u>(5</u>
<u> x 3)</u> + (10 ÷
)
(16
) + <u>(10 ÷ </u>
<u>)</u>
<u>(16</u>
<u>) + (20)</u>
36 
F[c(p)] = 0.81p. I hope this helps :) Please give me a rate and thanks :P