i dont know the answer, but i reccommend using mathpapa.com as they give you the answer PLUS the explaination.
set f(x) equal to y
y = 19/ x^3
swap x and y
x = 19/y^3
make y the subject
xy^3 = 19
y^3 = 19/x
![y = \sqrt[3]{ \frac{19}{x} }](https://tex.z-dn.net/?f=y%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B19%7D%7Bx%7D%20%7D%20)
then just replace y with f^-1(x)
![f(x) = \sqrt[3]{ \frac{19}{x} }](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B19%7D%7Bx%7D%20%7D%20)
hope this helped! have a good day ~ •lipika•
Answer:
Jake is 9, and Jake's dad is 43.
Step-by-step explanation:
Ok, let's start off by putting a variable for Jack's age, A.
We know that Jack's father is 2 less than 5 times, so we can write his as 5x -2.
Now let's make an equation:
52 = x + 5x - 2
We need to isolate the x-values so we need to add 2 on both sides:
54= x + 5x
No we need to add the like terms:
54 = 6x
Finally, we just divide by 6 on each side.
Now we know X = 9 but we're not done yet :)
So because Jake's dad is almost 5 times as much, we first multiply Jack's age by 5. We get 45 but we need to subtract 2 which leaves us with 43.
Answer:
f(x) = 2x^2 - 3x + 1
Step-by-step explanation:
The root 1 is associated with the factor (x - 1).
The root 1/2 is associated with the factor (x - 1/2), which in turn is equivalent to (2x -1)
The quadratic in question is f(x) = (x - 1)(2x - 1). To write this in standard form, perform the indicated multiplication:
f(x) = 2x^2 - 2x - x + 1, or f(x) = 2x^2 - 3x + 1
