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kow [346]
4 years ago
5

What will happen if a positively charged particle is placed next to a negatively charged particle?

Physics
1 answer:
zimovet [89]4 years ago
8 0

Answer:

If possible, they will attempt to bond to cancel out each other's charges

Explanation:

Please mark for Brainliest!! :D Thanks!!

For more questions or more information, please comment below!

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Does natural selection produce a change in individuals or populations?
butalik [34]

Explanation:

Natural selection is the process through which populations of living organisms adapt and change. Individuals in a population are naturally variable, meaning that they are all different in some ways. This variation means that some individuals have traits better suited to the environment than others

6 0
3 years ago
According to the scientific theory of atoms, which of the following statements
olga_2 [115]

Answer:

gikjjc hgc  jmjuyv

Explanation:

5 0
3 years ago
A child rides a bicycle from rest, reaching a velocity of 3.8 m/s [E] after 4.7 s. What is the acceleration of the bicycle?
Maurinko [17]

Answer:

0.81 m/s^2

Explanation:

A child rides a bicycle from rest

The child reaches a velocity of 3.8m/s

The time is 4.7 secs

Therefore the acceleration can be calculated as follows

v= u + at

3.8= 0 + a(4.7)

3.8= 0 + 4.7a

3.8-0= 4.7a

3.8= 4.7a

a= 3.8/4.7

= 0.81 m/s^2

Hence the acceleration is 0.81 m/s^2

8 0
3 years ago
A cyclist is taking part in the Tour de France, which is a bicycle race that takes place every year.
marishachu [46]
Solve the following word problems.
1. The ratio of red marbles and blue marbles that Carlo has is 8: 3. When he
exchanged 35 red marbles for 20 blue marbles from his brother, he was left with
equal number of red and blue marbles.
How many red and blue marbles did he have at the beginning
How many red and blue marbles did he have now
5 0
3 years ago
A girl (mass M) standing on the edge of a frictionless merry-go-round (radius R, rotational inertia I) that is not moving. She t
vladimir1956 [14]

a) \omega=\frac{-mvR}{I+MR^2}

b) v=\frac{-mvR^2}{I+MR^2}

Explanation:

a)

Since there are no external torques acting on the system, the total angular momentum must remain constant.

At the beginning, the merry-go-round and the girl are at rest, so the initial angular momentum is zero:

L_1=0

Later, after the girl throws the rock, the angular momentum will be:

L_2=(I_M+I_g)\omega +L_r

where:

I is the moment of inertia of the merry-go-round

I_g=MR^2 is the moment of inertia of the girl, where

M is the mass of the girl

R is the distance of the girl from the axis of rotation

\omega is the angular speed of the merry-go-round and the girl

L_r=mvR is the angular momentum of the rock, where

m is the mass of the rock

v is its velocity

Since the total angular momentum is conserved,

L_1=L_2

So we find:

0=(I+I_g)\omega +mvR\\\omega=\frac{-mvR}{I+MR^2}

And the negative sign indicates that the disk rotates in the direction opposite to the motion of the rock.

b)

The linear speed of a body in rotational motion is given by

v=\omega r

where

\omega is the angular speed

r is the distance of the body from the axis of rotation

In this problem, for the girl, we have:

\omega=\frac{-mvR}{I+MR^2} is the angular speed

r=R is the distance of the girl from the axis of rotation

Therefore, her linear speed is:

v=\omega R=\frac{-mvR^2}{I+MR^2}

5 0
3 years ago
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