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4 years ago

What will happen if a positively charged particle is placed next to a negatively charged particle?

Physics

1 answer:

zimovet [89]4 years ago

8 0

Answer:

If possible, they will attempt to bond to cancel out each other's charges

Explanation:

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Fill in the blank. When using a wrench if you double the length of the wrench (effort arm), you have ______ the required force t

OlgaM077 [116]

Answer:

halved

Explanation:

the formula

8 0

3 years ago

Which statement is true? CTP hydrolysis can be a source of chemical energy. dATP is the most common source of chemical energy in

Gemiola [76]

1. Statement A is true.

When GTP is hydrolysed, the free energy of hydrolyses is used to power or drive reactions that are favourable energetically.

2. Statement B it true.

ATP is a complex chemical that gives energy for the activities in many living cells. During hydrolyses, chemical energy stored in the energy-rich phosphoanhydride is released. Hence its a common source of chemical energy in cells.

3. Statement C is false.

The hydrolyses of ATP to ADP in the presence of phosphate, releases one mole of ATP which is estimated to be -57Kj/mol not 14Kj/mol. Below is the equation;

ATP + H20 -----> ADP + Pi + Free energy.

4. Statement D is false.

GTP stands for guanosine triphosphate.

ATP stands for adenosine triphosphate

ADP stands for adenosine diphosphate.

3 0

4 years ago

Consider a wire of length L = 0.30m that runs north-south on a horizontal surface. There is a current of I = 0.50A flowing north

ankoles [38]

Answer:

Part a)

$F = 4.6 \times 10^{-6} N$

Part b)

$F = 8.2 \times 10^{-2} N$

Explanation:

Part a)

As we know that the magnetic force on the current carrying wire is given as

$F = i(\vec L \times \vec B)$

so we have

$F = iLB sin\theta$

$F = (0.50)(0.30)(0.5 \times 10^{-4}) sin38$

so we have

$F = 4.6 \times 10^{-6} N$

Part b)

Now magnetic field is changed to 0.55 T

so we will have

$F = (0.50)(0.30)(0.55) sin90$

$F = 8.2 \times 10^{-2} N$

3 0

3 years ago

If an ocean wave passes a stationary point every 5 s and has a velocity of 10 m/s, what is the wavelength of the wave

Rainbow [258]

Answer:

As Per Provided Information

Velocity of wave v is 10m/s

These ocean wave passes a stationary point every 5 s ( It's time period)

First we calculate the frequency of ocean wave .

Using Formulae

$\blue{\boxed{\bf \: \nu = \cfrac{1}{v}}}$

here

v is the velocity of wave .

$\sf\longrightarrow \nu \: = \cfrac{1}{10} \\ \\ \\ \sf\longrightarrow \nu \: = 0.1Hz$

Now calculating the wavelength of the wave .

Using Formulae 

$\boxed{ \bf \lambda = \cfrac{v}{ \nu}}$

Substituting the value and we obtain

$\sf \longrightarrow \lambda \: = \cfrac{10}{0.1} \\ \\ \\ \sf \longrightarrow \lambda \: = \cancel\cfrac{10}{0.1} \\ \\ \\ \sf \longrightarrow \lambda \: =100m$

Therefore,

Wavelength of the wave is 100 metres.

8 0

3 years ago

The line where the Earth and sky seem to meet forms the:

babunello [35]

The ocean and the sky provide a clean, flat line where the Earth seems to meet the sky. If you're standing on the beach looking out at the sea, the part of the sea that "touches" the horizon is called the offing

6 0

3 years ago

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