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Zepler [3.9K]
3 years ago
13

Someone help me please

Mathematics
1 answer:
Mariana [72]3 years ago
8 0

Answer: I think 10

Step-by-step explanation: cuz area is length x height and basically you just do square root of 100 Bc thags a square so the sides should be equal

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scoray [572]
The answer is letteer C. You just have to multiply 9 and pi
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2 years ago
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A pill has the shape of a cylinder with a hemisphere at each end. The height of the cylindrical portion is 12mm and the overall
Volgvan

Answer:

The volume of the pill is V=452\ mm^{3}

Step-by-step explanation:

Find the volume of the pill in cubic millimeters

we know that

The volume of the pill is equal to the volume of the cylinder plus the volume of a sphere (two hemisphere is equal to one sphere)

so

we have

V=\frac{4}{3}\pi r^{3}+\pi r^{2}h

r= (18-12)/2=3\ mm\\ h=12\ mm

assume

\pi =3.14

substitute

V=\frac{4}{3}(3.14)(3)^{3}+(3.14)(3)^{2}(12)\\V=452\ mm^{3}

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3 years ago
The average number of Saturday night shootings is 5 a night. What’s the chance that there will be a need for exactly 3 shootings
pishuonlain [190]

Answer:

0.14

Step-by-step explanation:

Using the poisson probability relation :

P(x = x) = (λ^x * e^-λ) ÷ x!

From the question ; mean, λ = 5 ; x = 3

Hence,

P(x = 3) = (5^3 * e^-5) ÷ 3!

P(x = 3) = (125 * 0.0067379) / 6

P(x = 3) = 0.8422375 / 6

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2 years ago
Pineview Middle School has 158 fewer students enrolled than Wellington Middle School. If Pineview Middle has 1039 students enrol
vampirchik [111]
1039 + 158 = 1197 students
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Yolanda owns 4 rabbits. She expects the number of rabbits to double every year.
jok3333 [9.3K]
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y=Years that have passed by { y ≥ 0 }

R=f(y) --> R is a function of y.
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Note that when:

y=0, R=4 ---> Point: (0, 4)

y=1, R=8 ---> Point (1, 8)

y=2, R=16 ---> Point (2, 16)

y=3, R=32 ---> Point (3, 32)

y=4, R=64 ---> Point (4, 64)

--------------------------------------------

So the equation you want is going to form a curved graph.

That equation is:

R={ 2 }^{ y+2 }

<em>*You can test out this function on any decent graphing software.</em>

7 0
3 years ago
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