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vitfil [10]
3 years ago
12

Please help me as soon as possible! :)

Mathematics
1 answer:
AleksAgata [21]3 years ago
6 0

Answer:

-8,-7,-5,-3,-2

-80,-40,20,60

Step-by-step explanation:

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Help as soon as possible pleaseee
KiRa [710]

Answer:

(3x + 2)(x-4)

Step-by-step explanation:

3x² - 10x - 8 = 0

(splitting the middle term)

3x² -12x + 2x -8 = 0

3x(x-4) + 2(x-4) = 0

(3x + 2)(x-4) = 0

(3x + 2)(x-4) is the correct answer (option a)

3 0
3 years ago
Read 2 more answers
Simplify the polynomial (4n2 + 3n - 5) - (2n2 + 3n+ 6)
saul85 [17]

Answer:

2n^2 - 11

steep by steep explanation

=(4n^2 + 3n -5) -(2n^2 + 3n +6)

= 4n^2 +3n -5 - 2n^2 - 3n -6

= 2n^ - 11

3 0
3 years ago
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What is 2 to the power of 2?
padilas [110]
Okay, so you are talking about exponents, so what you are talking about is 2², to find the answer to the exponent you multiply the same number as many times as the exponent (little number) says, so in here we are going to multiply 2 x 2 and the answer is 4. So 2 to the power of 2 is 4.
5 0
3 years ago
The ratio of sues age to her fathers age is 2:7 in three years their ages will total 60, how old is sue and her dad right now
USPshnik [31]
Sue is 12 and her father is 42
7 0
4 years ago
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One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times sm
sergey [27]

One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle. Then the lines are parallel

<h3><u>Solution:</u></h3>

Given that, One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle.  

We have to prove that the lines are parallel.

If they are parallel, sum of the described angles should be equal to 180 as they are same side exterior angles.

Now, the 1st angle will be 1/6 of right angle is given as:

\begin{array}{l}{\rightarrow 1^{\text {st }} \text { angle }=\frac{1}{6} \times 90} \\\\ {\rightarrow 1^{\text {st }} \text { angle }=15 \text { degrees }}\end{array}

And now, 15 degrees is 11 times smaller than the other  

Then other angle = 11 times of 15 degrees

\text {Other angle }=11 \times 15=165 \text { degrees }

Now, sum of angles = 15 + 165 = 180 degrees.

As we expected their sum is 180 degrees. So the lines are parallel.

Hence, the given lines are parallel

5 0
3 years ago
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