Please help immediately this is 2 days late
1 answer:
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Answer:
0.6804
Step-by-step explanation:
Given that Margie is practicing for an upcoming tennis tournament. Her first serve is good 20 out of 30 times on average.
Since each trial is independent and there are two outcomes, X no of good serves is binomial with n=6 and p =2/3
Required probability
= Prob that atleast four of 6 times good serve
=
=
Formula used:
P(X=r) =
Answer:
a) It can be used because np and n(1-p) are both greater than 5.
Step-by-step explanation:
Binomial distribution and approximation to the normal:
The binomial distribution has two parameters:
n, which is the number of trials.
p, which is the probability of a success on a single trial.
If np and n(1-p) are both greater than 5, the normal approximation to the binomial can appropriately be used.
In this question:
So, lets verify the conditions:
np = 201*0.45 = 90.45 > 5
n(1-p) = 201*(1-0.45) = 201*0.55 = 110.55 > 5
Since both np and n(1-p) are greater than 5, the approximation can be used.