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fiasKO [112]
3 years ago
15

A sporting goods store received an order of 80 baseball caps, of which 12 were green. If 1 of the 80 caps is selected at random,

what is the probability it will NOT be green?
15%
68%
85%
88%
Mathematics
1 answer:
DochEvi [55]3 years ago
3 0

Answer:

85%

Step-by-step explanation:

If the sporting goods store received a lot of 80 baseball caps... and 12 of them were green that means that 68 (80-12) were NOT green.

Thus, the probably to randomly pick up a cap that is NOT green is 68 out of 80...

68/80 = 17/20 = 85%

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3 years ago
Problem 1: Use the Laplace Transforms to solve:
Leokris [45]

Transforming the ODE yields

L\left\{y'' - y'\right\} = L\left\{e^{-3t}\right\}

(s^2 Y(s) - sy(0) - y'(0)) - (s Y(s) - y(0)) = \dfrac1{s+3}

(s^2 - s) Y(s) = \dfrac1{s+3}

Y(s) = \dfrac1{(s^2 - s)(s+3)} = \dfrac1{s(s-1)(s+3)}

Partial fractions:

Y(s) = \dfrac as + \dfrac b{s-1} + \dfrac c{s+3}

\implies 1 = a(s-1)(s+3) + b s(s+3) + c s(s - 1)

\implies 1 = -3 a + (2 a + 3 b - c) s + (a + b + c) s^2

\implies \begin{cases}-3a=1 \\ 2a+3b-c=0 \\ a+b+c=0\end{cases} \implies a=-\dfrac13, b=\dfrac14, c=\dfrac1{12}

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3 0
2 years ago
Eli was using a recipe for a large smoothie that required three and three–thirds bananas. Instead of making one smoothie, Eli de
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Answer:

three small smoothies require one and one-third bananas.

Step-by-step explanation:

Assuming that the three small smoothies are equal, and their sum equals the one large smoothie;

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three-thirds mean that out of three parts, three parts were selected. Therefore, three-thirds is the same thing as a whole or 1

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Therefore, the one large smoothie required 4 bananas.

Large smoothie = 4 bananas

three small smoothies = \frac{4}{3} = 1 \frac{1}{3}

Hence, three small smoothies require one and one-third bananas.

6 0
3 years ago
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Answer:

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