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Alexeev081 [22]
3 years ago
13

What is 4/15 equivalent to

Mathematics
1 answer:
max2010maxim [7]3 years ago
8 0

Answer:

.2666667 or 26.66667%

Step-by-step explanation:

4/15 cant be simplified further. the denominator is divisible by 5 or 3, while the numerator is only divisible by 2. You can't make it smaller.

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What is the solution of this equqtion? 1w= -17​
devlian [24]

Answer:

-17

Step-by-step explanation:

1w= -17

(1)(-17)=

-17

5 0
3 years ago
Read 2 more answers
A cube has a side length of x inches. What expression represents the total volume, in cubic inches, of the cube?
Pie

Answer:

Volume = x^3 cubic inches

Step-by-step explanation:

A cube is the 3D version of a square. Since one side length is x inches, all the other side lengths are same, x inches each.

We know,

Volume = area of base * height

THe base is a square and the area is side * side. We know each side is x, so we have:

Area of Square = Area of Base = x * x = x^2

Now, we know height is also same side length, x, thus the volume becomes:

Volume = area of base * height

Volume = x^2*x

We add the exponents when we have same base multiplied, so the expression for volume becomes:

Volume = x^2*x=x^3

8 0
3 years ago
Estimate the student's walking pace, in steps per minute, at 3:20 p.m. by averaging the slopes of two secant lines from part (a)
ehidna [41]

This question is incomplete, the complete question is;

A student bought a smart-watch that tracks the number of steps she walks throughout the day. The table shows the number of steps recorded (t) minutes after 3:00 pm on the first day she wore the watch.

t (min)       0          10          20         30         40

Steps   3,288    4,659    5,522    6,686    7,128

a) Find the slopes of the secant lines corresponding to the given intervals of t.

1) [ 0, 40 ]

11) [ 10, 20 ]

111) [ 20, 30 ]

b) Estimate the student's walking pace, in steps per minute, at 3:20 pm by averaging the slopes of two secant lines from part (a). (Round your answer to the nearest integer.)

Answer:

a)

1) for [ 0, 40 ], slope is 96

11) for [ 10, 20 ],  slope is 86.3

111) for  [ 20, 30 ], slope is 116.4

b) the student's walking pace is 101 per min

Step-by-step explanation:

Given the data in the question;

t (min)       0          10          20         30         40

Steps   3,288    4,659    5,522    6,686    7,128

SLOPE OF SECANT LINES

1) [ 0, 40 ]

slope =  ( 7,128 - 3,288 ) / ( 40 - 0

= 3840 / 40 = 96

Hence slope is 96

11)  [ 10, 20 ]

slope = ( 5,522 - 4,659 ) / ( 20 - 10 )

= 863 / 10 = 86.3

Hence slope is 86.3

111)  [ 20, 30 ]

slope = ( 6,686 - 5,522 ) / ( 30 - 20 )

= 1164 / 10 = 116.4

Hence slope is 116.4

b)

Estimate the student's walking pace, in steps per minute, at 3:20 pm by averaging the slopes of two secant lines from part .

Since this is recorded after 3:00 pm

{ 3:20 - 3:00 = 20 }

so t = 20 min

so by average;

we have ( [ 10, 20 ] + [ 20, 30 ] ) /2

⇒ ( 86.3 + 116.4 ) / 2

= 202.7 /2

= 101.35 ≈ 101

Therefore, the student's walking pace is 101 per minutes

3 0
3 years ago
Plz help. Thank you!
NARA [144]
The new surface area will be 9 times the old surface area.

So A or #1
3 0
3 years ago
When Poll Pasked students to identify their favorite kind
Arada [10]

Answer:

120 students

Step-by-step explanation:

3 0
3 years ago
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