The first one is 1.12867 because you need to set it up like this.
4=3.14(x)squared
4/3.14=x(squared)
x=1.12867
The second one is done simply by multiplying it out.
A=3.14(3x)squared
A=3.14(9x[squared])
A=28.26x[squared] -The squared is referring to the x.
Answer:
c and b
Step-by-step explanation:
Answer:
Its 90
Step-by-step explanation:
<u>EXPLANATION</u><u>:</u>
In ∆ ABC , ∠ABC = 40°
∠ACD is an exterior angle formed by extending BC to D
We know that
The exterior angle of a triangle formed by extending one side is equal to the sum of the opposite interior angles.
∠ACD = ∠CAB + ∠ABC
⇛50° = x° + 40°
⇛x° = 50°-40°
<h3>⇛x° = 10°</h3>
and
In ∆ ACD , AC = CD
⇛ ∠CDA = ∠CAD
Since the angles opposite to equal sides are equal.
Let ∠CDA = ∠CAD = A°
We know that
The sum of all angles in a triangle is 180°
In ∆ ACD,
∠CDA +∠CAD + ∠ACD = 180°
A°+A°+50° = 180°
⇛2A°+50° = 180°
⇛2A° = 180°-50°
⇛2A° = 130°
⇛A° = 130°/2
⇛A° = 65°
now,
∠CDA = ∠CAD = 65°
∠BAC + ∠CAD+y = 180°
Since angles in the same line
10°+65°+y = 180°
⇛75°+y =180°
⇛y = 180°-75°
<h3>⇛y = 105°</h3>
<u>Answer</u><u>:</u> Hence, the value of “x” & “y” will be 10° and 105° respectively.
Answer:
$6.07/hr. if I understand the question properly. See below.
Step-by-step explanation:
I don't see the question, but will assume we want to find Larisa's base pay. The $7/hr given is the average for the work sequence noted in the problem. If this is incorrect, ignore the answer.
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Let x be Larisa's base salary. We are told, I think, that in one stretch of time Larisa earned an average of $7/hour. That was composed of:
<u>Hours</u> <u>Rate($/hr)</u>
40 x
3 1.5x
<u> 6 </u> 2x
49
Her total income over this period would be:
40x +3(1.5x) + 6(2x) [The hours worked times the pay rate for each period]
Her average income per hour would be:
(40x +3(1.5x) + 6(2x))/49
which we are told is $7/hr.
(40x +3(1.5x) + 6(2x))/49 = 7
40x + 4.5x + 12x = 343
56.5x = 343
x = $6.07/hr
